Suppose a dresser drawer has blue shirts, yellow shirts, red shirts, and green shirts so that if a shirt is pulled from the drawer at random, each color has an equal chance of being drawn. P(Green) = P(Blue) = P(Red) = P(Yellow) = ¼. Complete parts (a) – (d) to create a probability distribution for the number of yellow shirts if two shirts are pulled from the drawer at random (replacing the shirt after each draw). a. List each possible outcome for the colors of the shirts if two shirts are drawn randomly from the drawer. The teacher said there should be total of 16 outcomes, not 9 or 10. In my original answer, I have 10 outcomes when there should be 16. c.Find the probability of each event (not the probability from each outcome) from part (b). For my first answer, I had the probability of each outcome, and I should have the probability of each event.

A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
Section: Chapter Questions
Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
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Suppose a dresser drawer has blue shirts, yellow shirts, red shirts, and green shirts so that if a shirt is pulled from the drawer at random, each color has an equal chance of being drawn. P(Green) = P(Blue) = P(Red) = P(Yellow) = ¼. Complete parts (a) – (d) to create a probability distribution for the number of yellow shirts if two shirts are pulled from the drawer at random (replacing the shirt after each draw).

a. List each possible outcome for the colors of the shirts if two shirts are drawn randomly from the drawer. The teacher said there should be total of 16 outcomes, not 9 or 10. In my original answer, I have 10 outcomes when there should be 16.

c.Find the probability of each event (not the probability from each outcome) from part (b). For my first answer, I had the probability of each outcome, and I should have the probability of each event.

 

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