Suppose a 764 keV electron and a 812 kev positron (anti-electron) collide and annihilate each other, producing two identical photons. Assuming the process is 100% efficient, find the frequency of these new photons, in Hz. Why must two photons be created?
Suppose a 764 keV electron and a 812 kev positron (anti-electron) collide and annihilate each other, producing two identical photons. Assuming the process is 100% efficient, find the frequency of these new photons, in Hz. Why must two photons be created?
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![Suppose a 764 keV electron and a 812 kev positron (anti-electron) collide and annihilate each other, producing two identical photons. Assuming the process is
100% efficient, find the frequency of these new photons, in Hz.
Why must two photons be created?](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F99651f1d-cdac-42ba-8d41-e859405037ca%2Fe569b249-1130-4dd4-a320-419e19e571ac%2Fe2mtqa9_processed.png&w=3840&q=75)
Transcribed Image Text:Suppose a 764 keV electron and a 812 kev positron (anti-electron) collide and annihilate each other, producing two identical photons. Assuming the process is
100% efficient, find the frequency of these new photons, in Hz.
Why must two photons be created?
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