Supply the missing parts Given: AT = BC CO bisects ZACB Prove: AACO = ABCO Proof: Since, AC = BC, CO bisects LACB, Hence ZACO = LBCO by the 1, property. Thus, We have AC BC. LACO ZBCO, CO CO. then AACO AHCO by 3. Also 2. by reflexive

Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
ChapterP: Preliminary Concepts
SectionP.CT: Test
Problem 1CT
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Answer the blank in the statement. Answer number 1 only. 

Supply the missing parts.
Given: AC = BC
CO bisects ZACB
Prove: AACO = ABCO
Proof: Since, AC = BC, CO bisects LACB, Hence ACO = LBCO by the
Also 2.
by reflexive
property. Thus, We have AC = BC, LACO e ZBCO, CO = CO,
then AACO AHCO by 3.
Transcribed Image Text:Supply the missing parts. Given: AC = BC CO bisects ZACB Prove: AACO = ABCO Proof: Since, AC = BC, CO bisects LACB, Hence ACO = LBCO by the Also 2. by reflexive property. Thus, We have AC = BC, LACO e ZBCO, CO = CO, then AACO AHCO by 3.
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