Supplemental Material for Elementary Principles of Chemical Processes Example 3.5-3 Temperature Conversion and Dimensional Homogeneity kJ The heat capacity of hydrogen gas in units of is approximately given by the mol-"C following relationship, where T is the temperature measured in °C. kJ =0.02884 +7.65x10"T("C) mol "C BTU (a) Derive a formula for heat capacity in units of Ib. "F Strategy We can use unit conversions, molecular weight, and temperature conversion formulas to solve this problem. Solution We can substitute the relationship T*C) = TCF)-32 into the above equation. We can also 1.8 use the molecular weight with energy and mass unit conversions to give: T('F) - 32] kJ mol-C Btu °C 1.8°F 2.016g mol C, -0.02884 +7.65x10 1.8 kJ Ib. T(*F)-32 Btu C, = 0.02884 +7.65x10 1.8 Ib "F Btu C, -L- Ib "F BTU (b) Derive a formula for heat capacity in units of Ib. R Strategy We can use the answer for part (a) to derive the new formula. Solution We can substitute the relationship T("F) = T(R)-459.67 into the above equation. This gives: Daniel López Gaxiola Student View Jason M. Keith Supplemental Material for Elementary Principles of Chemical Processes c, -[34197+ 5.039x10“TCÐ], Btu Ib F Btu "F c, =[34197+5.039x10“ T(R) -. 'Ib. °FR T(R) Btu C, -I- Ib R Note that the values are the same since AT in R is the same as AT in "F.

Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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Answer the blank in both a and b, show solutions. This is about chemical engineering calculations.
Supplemental Material for Elementary Principles of Chemical Processes
Example 3.5-3 Temperature Conversion and Dimensional Homogeneity
kJ
The heat capacity of hydrogen gas in units of
is approximately given by the
mol-C
following relationship, where T is the temperature measured in °C.
kJ
=0.02884 +7.65x10 T("C)
mol "C
BTU
(a) Derive a formula for heat capacity in units of
Ib. "F
Strategy
We can use unit conversions, molecular weight, and temperature conversion formulas to
solve this problem.
Solution
T("F)- 32
We can substitute the relationship T("C) =
into the above equation. We can also
1.8
use the molecular weight with energy and mass unit conversions to give:
C, -0.02884 + 7.65x10 TCF)-32] k
mol. "C
Btu °C mol
1.8
kJ
1.8°F 2.016g
Ib.
T(*F)-32] Btu
Jib. "F
C, = 0.02884 +7.65x10
1.8
C, -[ +.
T'F) Bu
'Ib F
BTU
(b) Derive a formula for heat capacity in units of-
Ib R
Strategy
We can use the answer for part (a) to derive the new formula.
Solution
We can substitute the relationship T('F) = T(R)-459.67 into the above equation. This gives:
Daniel López Gaxiola
Jason M. Keith
Student View
Supplemental Material for Elementary Principles of Chemical Processes
Btu
C, -[34197 + 5.039x10*T(°F];
Ib °F
Btu F
C, =[3.4197+5.039x10 [T(R)-
Ib. °FR
T(R)-
T(R)) Blu
Ib R
Note that the values are the same since AT in R is the same as AT in °F
Transcribed Image Text:Supplemental Material for Elementary Principles of Chemical Processes Example 3.5-3 Temperature Conversion and Dimensional Homogeneity kJ The heat capacity of hydrogen gas in units of is approximately given by the mol-C following relationship, where T is the temperature measured in °C. kJ =0.02884 +7.65x10 T("C) mol "C BTU (a) Derive a formula for heat capacity in units of Ib. "F Strategy We can use unit conversions, molecular weight, and temperature conversion formulas to solve this problem. Solution T("F)- 32 We can substitute the relationship T("C) = into the above equation. We can also 1.8 use the molecular weight with energy and mass unit conversions to give: C, -0.02884 + 7.65x10 TCF)-32] k mol. "C Btu °C mol 1.8 kJ 1.8°F 2.016g Ib. T(*F)-32] Btu Jib. "F C, = 0.02884 +7.65x10 1.8 C, -[ +. T'F) Bu 'Ib F BTU (b) Derive a formula for heat capacity in units of- Ib R Strategy We can use the answer for part (a) to derive the new formula. Solution We can substitute the relationship T('F) = T(R)-459.67 into the above equation. This gives: Daniel López Gaxiola Jason M. Keith Student View Supplemental Material for Elementary Principles of Chemical Processes Btu C, -[34197 + 5.039x10*T(°F]; Ib °F Btu F C, =[3.4197+5.039x10 [T(R)- Ib. °FR T(R)- T(R)) Blu Ib R Note that the values are the same since AT in R is the same as AT in °F
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