Summary: MCA with AC Sources The circuit in Figure 3 is driven by two voltage sources: Va1 = 25.00 cos(400t +53.13°) V vo2 = 18.03 cos(400t + 33.69°) V (a) Rewrite this circuit in the "phasor world" (i.e. with black box impedances to replace all passive elements and phasor labels for voltage values vg1, v92 and vo) (b) Use Mesh Current Analysis to set up (do NOT solve) as many linear equations as needed to find values for mesh current values I, and Ig. Write these equations in the form: Figure 3 50 µF 50 mlI ell gl 150 2 'g2 (phasor) I, + (phasor) = phasor (c) Briefly (a few phrases, equations, diagrams) describe how you would use the information from part (b) to solve for voltage vo

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Summary: MCA with AC Sources
The circuit in Figure 3 is driven by two voltage sources:
Va1 = 25.00 cos(400t + 53.13°) V
v92 = 18.03 cos(400t + 33.69°) V
(a) Rewrite this circuit in the "phasor world" (i.e. with black box
impedances to replace all passive elements and phasor
labels for voltage values vg1, v92 and vo)
(b) Use Mesh Current Analysis to set up (do NOT solve) as
many linear equations as needed to find values for mesh
current values I, and Ig. Write these equations in the form:
Figure 3
50 µF
50 mII
ell
gl
150 2
B
g2
(phasor) I, + (phasor) I, = phasor
(c) Briefly (a few phrases, equations, diagrams) describe how
you would use the information from part (b) to solve for
voltage vo
Transcribed Image Text:Summary: MCA with AC Sources The circuit in Figure 3 is driven by two voltage sources: Va1 = 25.00 cos(400t + 53.13°) V v92 = 18.03 cos(400t + 33.69°) V (a) Rewrite this circuit in the "phasor world" (i.e. with black box impedances to replace all passive elements and phasor labels for voltage values vg1, v92 and vo) (b) Use Mesh Current Analysis to set up (do NOT solve) as many linear equations as needed to find values for mesh current values I, and Ig. Write these equations in the form: Figure 3 50 µF 50 mII ell gl 150 2 B g2 (phasor) I, + (phasor) I, = phasor (c) Briefly (a few phrases, equations, diagrams) describe how you would use the information from part (b) to solve for voltage vo
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