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1. (a) A sinusoidal voltage with Veff = 10V is connected across Z₁ = 1 + j as shown in figure(a) below. Find i₁, leff, p₁(t), P₁, Q₁, power factor pf₁, and S₁. (b) Repeat part (a) replacing the load Z₁ in (a) by Z₂ = 1-j as shown in figure (b) below. (c) Repeat part (a) after connecting in parallel Z₁ and Z₂2 as shown in figure (c). Let v = 10√2cos wt. V= 10 V V= 10 V Z 10 V 4/2 1½ 14 (a) (b) $₂ 45° P₁ P₂ 45° P₁ S=P = P₁ + P₂ Q₁ Q₂

1. (a) A sinusoidal voltage with Veff = 10V is connected across Z₁ = 1 + j as shown in figure(a) below. Find i₁, leff, p₁(t), P₁, Q₁, power factor pf₁, and S₁. (b) Repeat part (a) replacing the load Z₁ in (a) by Z₂ = 1-j as shown in figure (b) below. (c) Repeat part (a) after connecting in parallel Z₁ and Z₂2 as shown in figure (c). Let v = 10√2cos wt. V= 10 V V= 10 V Z 10 V 4/2 1½ 14 (a) (b) $₂ 45° P₁ P₂ 45° P₁ S=P = P₁ + P₂ Q₁ Q₂

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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1. (a) A sinusoidal voltage with Veff = 10V is connected across Z₁ = 1 + jas shown in figure(a) below. Find i₁, leff, p₁(t), P₁, Q₁, power factor pf₁, and S1. (b) Repeat part (a) replacing the load Z₁ in (a) by Z₂ = 1-j as shown in figure (b) below. (c) Repeat part (a) after connecting in parallel Z₁ and Z₂ as shown in figure (c). Let v = 10√2cos wt. V= 10 V V= 10 V Z 10 V won 4½ mit T 4½ (a) (b) (c) S₁ 1 P₁ 3 $₂ 45° P₂ 45° P₁ S=P = P₁ + P₂ P₂ 2₂
Transcribed Image Text:1. (a) A sinusoidal voltage with Veff = 10V is connected across Z₁ = 1 + jas shown in figure(a) below. Find i₁, leff, p₁(t), P₁, Q₁, power factor pf₁, and S1. (b) Repeat part (a) replacing the load Z₁ in (a) by Z₂ = 1-j as shown in figure (b) below. (c) Repeat part (a) after connecting in parallel Z₁ and Z₂ as shown in figure (c). Let v = 10√2cos wt. V= 10 V V= 10 V Z 10 V won 4½ mit T 4½ (a) (b) (c) S₁ 1 P₁ 3 $₂ 45° P₂ 45° P₁ S=P = P₁ + P₂ P₂ 2₂
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