sume that z-scores are normally distributed with a mean of 0 and a standard deviation of 1. P(- b< z < b) = 0.9856, find b (round your answer to 3 decimals). |
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Q: IQ is normally distributed with a mean of 100 and a standard deviation of 15. Suppose one individual…
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Q: The combined SAT scores for the students at a local high school are normally distributed with a mean…
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Q: What percentage of students from this school earn scores that fail to satisfy the admission…
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A: given: mean = 262 standard deviation = 15 to find P(X<270) days
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Q: The lengths of pregnancies in a small rural village are normally distributed with a mean of 262 days…
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- A distribution of values is normal with a mean of 214 and a standard deviation of 10.Find the probability that a randomly selected value is less than 203.P(X < 203) = Enter your answer as a number accurate to 4 decimal places. Answers obtained using exact z-scores or z-scores rounded to 3 decimal places are accepted.A professor believes the students in a statistics class this term are more creative than most other students attending the university. A previous study found that students at the university had a mean score of 35 on a standard creativity test, and the current class has an average score of 40 on this scale with an estimated population standard deviation of 7. The standard deviation of the distribution of means is 1.63. The t score is (40 – 35) / 7 = 0.71 (40 – 35) / 1.63 = 3.07 (40 – 35) / 72 = 5 / 49 = 0.10 (40 – 35) / 1.632 = 5 / 2.66 = 1.88Find the area of the shaded region. The graph to the right depicts IQ scores of adults, and those scores are normally distributed with a mean of 100 and a standard deviation of 15. 108 130 The area of the shaded region is |- (Round to four decimal places as needed.) Enter your answer in the answer box. ?
- The lengths of pregnancies in a small rural village are normally distributed with a mean of 266 days and a standard deviation of 12 days. A distribution of values is normal with a mean of 266 and a standard deviation of 12.What percentage of pregnancies last fewer than 270 days? P(X < 270 days) = %Enter your answer as a percent accurate to 1 decimal place (do not enter the "%" sign). Answers obtained using exact z-scores or z-scores rounded to 3 decimal places are accepted.The combined SAT scores for the students at a local high school are normally distributed with a mean of 1524 and a standard deviation of 305. The local college includes a minimum score of 1555 in its admission requirements. What percentage of students from this school earn scores that fail to satisfy the admission requirement? P(X < 1555) = % Enter your answer as a percent accurate to 1 decimal place (do not enter the "%" sign). Answers obtained using exact z- scores or z-scores rounded to 3 decimal places are accepted.The table below shows the summary statistics of the sales ($) made by company ABC in 2022. No. of month 12 134,562 135,000 48,997 95,000 185,000 90,000 Mean Median S.D Minimum Maximum Range The monthly profit should be adjusted by multiplying 0.88 then subtracting $30,000. Without calculating the profit for each month, find the new standard deviation of profit for 2022? (2 d.p.)
- IQ is normally distributed with a mean of 100 and a standard deviation of 15. Suppose one individual is randomly chosen. Let X = IQ of an individual. (a) Find the z-score for an IQ of 99, rounded to three decimal places. (b) Find the probability that the person has an IQ greater than 99. (c) Shade the area corresponding to this probability in the graph below. (Hint: The x- axis is the z-score. Use your z-score from part (a), rounded to one decimal place). Shade: Left of a value -1 -1.5 0 +). Click and drag the arrows to adjust the values. 1 2 (d) MENSA is an organization whose members have the top 2% of all IQs. Find the minimum IQ needed to qualify for the MENSA organization. (e) Sketch the graph, and write the probability statement. Edit Insert Formats B I U x₂ x² A => EM e & N 18 (f) The middle 50% of IQs fall between what two values? (g) Sketch the graph and write the probability statement. Edit Insert Formats BIUX₂ X² A E = = E EC P R N • Σ+ Σ Α Σ+ Σ ΑLet x = red blood cell (RBC) count in millions per cubic millimeter of whole blood. For healthy females, x has an approximately normal distribution with mean ? = 5.6 and standard deviation ? = 0.4. (d) Convert the z interval, z < −1.44, to an x interval. (Round your answer to one decimal place.) (e) Convert the z interval, 1.28 < z, to an x interval. (Round your answer to one decimal place.)Find the area of the shaded region. The graph to the right depicts IQ scores of adults, and those scores are normally distributed with a mean of 100 and a standard deviation of 15. Click to view page 1 of th - × The area of the shaded r Standard Normal Table (Page 1) NEGATIVE z Scores Standard Normal (z) Distribution: Cumulative Area from the LEFT .00 .01 02 .03 .04 .05 .06 .07 .08 .09 -3.50 and lower .0001 -3.4 .0003 .0003 .0003 .0003 .0003 .0003 -3.3 .0005 .0005 .0005 .0004 .0004 .0004 .0003 0004 .0003 .0004 .0003 .0004 .0002 .0003 -3.2 .0007 .0007 .0006 0006 .0006 .0006 .0006 .0005 .0005 .0005 -3.1 .0010 .0009 .0009 .0009 .0008 .0008 .0008 .0008 0007 .0007 -3.0 .0013 .0013 0013 .0012 0012 .0011 .0011 .0011 0010 0010 -2.9 .0019 0018 0018 .0017 .0016 .0016 .0015 .0015 .0014 .0014 -2.8 .0026 .0025 .0024 .0023 .0023 .0022 .0021 .0021 .0020 .0019 -2.7 .0035 .0034 .0033 .0032 .0031 .0030 .0029 .0028 .0027 .0026 -2.6 .0047 .0045 0044 .0043 .0041 .0040 .0039 .0038 .0037 .0036 -2.5 .0062…
- ACT scores range from 1 to 36 and are normally distributed where N (21.5, 5.4). SAT scores• range from 600 to 2400 and are normally distributed where N (1498, 316). Jorge scores 2090 on the SAT. If both tests measure the same thing, what score on the ACT is equivalent to Jorge's SAT score?The lengths of pregnancies in a small rural village are normally distributed with a mean of 269 days and a standard deviation of 17 days. A distribution of values is normal with a mean of 269 and a standard deviation of 17. What percentage of pregnancies last fewer than 272 days? P(X < 272 days) = % Enter your answer as a percent accurate to 1 decimal place (do not enter the "%" sign). Answers obtained using exact z-scores or z-scores rounded to 3 decimal places are accepted.
