sum1 = 0; for (k=1; k<=n; k*=2) for (j=1; j<=n; j++) sum1++; sum2 = 0; for (k=1; k<=n; k*=2) for (j=1; j<=k; j++) sum2++; [First is E"n = O(n log n). Second is - 2* = ©(n).] log n-1 k=1 k=0

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