Answered: Sufficient boron removal remains a…

Introduction to Chemical Engineering Thermodynamics

8th Edition

ISBN:9781259696527

Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart

Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart

Chapter1: Introduction

Section: Chapter Questions

Problem 1.1P

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Sufficient boron removal remains a serious challenge for seawater desalination. A plant is made to build a RO seawater desalination plant for typical seawater of 7 mg/L boron. The treatment target of boron is 0.5 mg/L in permeate. Boron rejection rates are 85% and 70% for sewater RO membrane and brackish RO membrane, respectively. Design a two-pass system (SWRO-first pass and BWRO second pass) to satisfy the boron requirement.

Expert Solution

Step 1: Step 1 of 3

To design a two-pass RO system for seawater desalination with a boron removal requirement of 0.5 mg/L, we can use the following steps:

Calculate the boron concentration in the permeate after the SWRO membrane:

   $S W R O space p e r m e a t e space b o r o n space c o n c e n t r a t i o n space equals space F e e d space b o r o n space c o n c e n t r a t i o n space asterisk times space left parenthesis 1 space minus space S W R O space b o r o n space r e j e c t i o n space r a t e right parenthesis$

    $S W R O space p e r m e a t e space b o r o n space c o n c e n t r a t i o n space equals space 7 space m g divided by L space asterisk times space left parenthesis 1 space minus space 0.85 right parenthesis space equals space 1.05 space m g divided by L$

Calculate the boron concentration in the permeate after the BWRO membrane:

     $B W R O space p e r m e a t e space b o r o n space c o n c e n t r a t i o n space equals space S W R O space p e r m e a t e space b o r o n space c o n c e n t r a t i o n space asterisk times space left parenthesis 1 space minus space B W R O space b o r o n space r e j e c t i o n space r a t e right parenthesis B W R O space p e r m e a t e space b o r o n space c o n c e n t r a t i o n space equals space 1.05 space m g divided by L space asterisk times space left parenthesis 1 space minus space 0.7 right parenthesis space equals space 0.315 space m g divided by L$