Subtract: x² – 2x + 1 x² – 1 We will factor each denominator, find the LCD, and build the rational expressions so each one has the LCD as its denominator. Since the denominators are different, we cannot subtract these rational expressions in their present form. We factor each denominator to find the LCD: x² – 2x + 1 = (x – 1)(x – 1) = (x – 1)2 x² – 1 = (x + 1)(x – 1) The greatest number of times x - 1 appears is twice. The greatest number of times x + 1 appears is once. The LCD is (x – 1)²(x + 1) or (x – 1)(x – 1)(x + 1). We now write each rational expression with its denominator in factored form. Then we multiply each numerator and denominator by the missing factor, so that each rational expression has a denominator of (x - 1)(x – 1)(x + 1). x + 1 x + 1 (x – 1)(x – 1) X - 4 (x + 1)(x – 1) x + 1 + 1 Write each denominator in factored form. x² – 2x + 1 1. x + 1 (x -– 1)(x – 1) x² + 2x + 1 (x – 1)(x – 1)(x + 1) (x² + 2x + 1) - (x² – 5x + 4) (x – 1)(x – 1)(x + 1) X - 4 Build each rational expression. (x + 1)(x – 1) X - 1 x2 - 5x + 4 (x + 1)(x – 1)(x – 1) Multiply the numerators using the FOIL method. Multiply the denominators. Subtract the numerators. Write the difference over the common denominator. x² + 2x + 1 – x² + 5x – 4 (x – 1)(x – 1)(x + 1) In the numerator, subtract the polynomials. %3D Combine like terms. The result does not simplify. (x – 1)(x – 1)(x + 1) a + 2 a2 - 4a + 4 a - Subtract:

Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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Question
x + 1
x2 - 2x + 1
х — 4
Subtract:
x2
- 1
We will factor each denominator, find the LCD, and build the rational expressions so each one has the LCD as its denominator.
Since the denominators are different, we cannot subtract these rational expressions in their present form.
We factor each denominator to find the LCD:
x2 - 2x + 1 = (x – 1)(x – 1) = (x – 1)2
x2 - 1 = (x + 1)(x – 1)
The greatest number of times x –
1 appears is twice.
The greatest number of times x + 1 appears is once.
The LCD is (x – 1)2(x + 1) or (x – 1)(x – 1)(x + 1).
We now write each rational expression with its denominator in factored form. Then we multiply each numerator and denominator by the missing factor, so that each rational
expression has a denominator of (x – 1)(x – 1)(x + 1).
х+ 1
х — 4
x + 1
х — 4
Write each denominator in factored form.
-
-
x2 - 2x + 1
1
(х — 1)(х — 1)
(x + 1)(x – 1)
x + 1
x + 1
X + 1
X - 4
X - 1
Build each rational expression.
-
(х — 1)(х — 1)
(x + 1)(x – 1)
х — 1
x2 - 5x + 4
x2 + 2x + 1
(x – 1)(x – 1)(x + 1)
(x² + 2x + 1) – (x² – 5x + 4)
(x – 1)(x – 1)(x + 1)
x2 + 2x + 1 – x² + 5x
(x – 1)(x – 1)(x + 1)
Multiply the numerators using the FOIL method.
Multiply the denominators.
(x + 1)(x – 1)(x – 1)
Subtract the numerators. Write the difference over the common denominator.
- 4
In the numerator, subtract the polynomials.
Combine like terms. The result does not simplify.
(x – 1)(x – 1)(x + 1)
a + 2
a - 1
Subtract:
a2 - 4a + 4
a2 - 4
Transcribed Image Text:x + 1 x2 - 2x + 1 х — 4 Subtract: x2 - 1 We will factor each denominator, find the LCD, and build the rational expressions so each one has the LCD as its denominator. Since the denominators are different, we cannot subtract these rational expressions in their present form. We factor each denominator to find the LCD: x2 - 2x + 1 = (x – 1)(x – 1) = (x – 1)2 x2 - 1 = (x + 1)(x – 1) The greatest number of times x – 1 appears is twice. The greatest number of times x + 1 appears is once. The LCD is (x – 1)2(x + 1) or (x – 1)(x – 1)(x + 1). We now write each rational expression with its denominator in factored form. Then we multiply each numerator and denominator by the missing factor, so that each rational expression has a denominator of (x – 1)(x – 1)(x + 1). х+ 1 х — 4 x + 1 х — 4 Write each denominator in factored form. - - x2 - 2x + 1 1 (х — 1)(х — 1) (x + 1)(x – 1) x + 1 x + 1 X + 1 X - 4 X - 1 Build each rational expression. - (х — 1)(х — 1) (x + 1)(x – 1) х — 1 x2 - 5x + 4 x2 + 2x + 1 (x – 1)(x – 1)(x + 1) (x² + 2x + 1) – (x² – 5x + 4) (x – 1)(x – 1)(x + 1) x2 + 2x + 1 – x² + 5x (x – 1)(x – 1)(x + 1) Multiply the numerators using the FOIL method. Multiply the denominators. (x + 1)(x – 1)(x – 1) Subtract the numerators. Write the difference over the common denominator. - 4 In the numerator, subtract the polynomials. Combine like terms. The result does not simplify. (x – 1)(x – 1)(x + 1) a + 2 a - 1 Subtract: a2 - 4a + 4 a2 - 4
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