substrate 1+ ax 38. Environmental studies are often concerned with the azyme is un- portional to relationship between the population of an urban area and the level of pollution. Suppose it is esti- mated that when p hundred thousand people live in a certain city, the average daily level of carbon monoxide in the air is o1-t, find ate con- L(p) = 0.07/p² +3 enzyme ppm. Further, assume that in t years there will be on rate

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Chapter1: Functions And Models
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Question 38

1.5 Function Building 69
(e.g., isomerase). Let f(x) be the amount of sub-
stance produced per minute as a function of the
substrate concentration x. To model this reaction
Take the reciprocals of the (x, y) data values
to get the corresponding (t, z) values. Use
technology to fit a line to the (t, z) data. If this
line is given by z = c + dt,use your work in
bx
rate, assume that enzymes are either “occupied"
(i.e., processing a substrate particle) or are "unoc-
cupied" (i.e., waiting to bind to another substrate
particle).
66
a to find the parameters a and b in y
1+ ax
38. Environmental studies are often concerned with the
a. Lett be the fraction of time that an enzyme is un-
occupied. Assuming that 1 – t is proportional to
tx, find t as a function of x.
relationship between the population of an urban
area and the level of pollution. Suppose it is esti-
mated that when p hundred thousand people live
in a certain city, the average daily level of carbon
-
b. Assuming that f(x) is proportional to 1 – t, find
an expression for f(x).
-
monoxide in the air is
c. Below are data for glucose-6-phosphate con-
verted to fructose-6-phospate by the enzyme
phosphoglucose isomerase.
L(p) = 0.07/p² +3
ppm. Further, assume that in t years there will be
Substrate concentration
Reaction rate
(micromolar)
(micromolar/minute)
p(t) = 1+0.02t³
0.08
0.15
hundred thousand people in the city. Based on these
assumptions, what level of air pollution should be
expected in four years?
0.12
0.21
0.54
0.70
1.23
1.1
39. The volume, V, of a certain cone is given by
1.82
1.3
2.72
1.5
4.94
1.7
V(h) :
12
=
10.00
1.8
Using linear regression on the transformed
data, the uptake rate can be approximated by
Suppose the height is expressed as a function of
time, t, by h(t) = 2t.
a. Find the volume when t = 2.
1.95x
f(x) =
Graph this function against
Express the volume as a function of elapsed time
1+0.95x
Transcribed Image Text:1.5 Function Building 69 (e.g., isomerase). Let f(x) be the amount of sub- stance produced per minute as a function of the substrate concentration x. To model this reaction Take the reciprocals of the (x, y) data values to get the corresponding (t, z) values. Use technology to fit a line to the (t, z) data. If this line is given by z = c + dt,use your work in bx rate, assume that enzymes are either “occupied" (i.e., processing a substrate particle) or are "unoc- cupied" (i.e., waiting to bind to another substrate particle). 66 a to find the parameters a and b in y 1+ ax 38. Environmental studies are often concerned with the a. Lett be the fraction of time that an enzyme is un- occupied. Assuming that 1 – t is proportional to tx, find t as a function of x. relationship between the population of an urban area and the level of pollution. Suppose it is esti- mated that when p hundred thousand people live in a certain city, the average daily level of carbon - b. Assuming that f(x) is proportional to 1 – t, find an expression for f(x). - monoxide in the air is c. Below are data for glucose-6-phosphate con- verted to fructose-6-phospate by the enzyme phosphoglucose isomerase. L(p) = 0.07/p² +3 ppm. Further, assume that in t years there will be Substrate concentration Reaction rate (micromolar) (micromolar/minute) p(t) = 1+0.02t³ 0.08 0.15 hundred thousand people in the city. Based on these assumptions, what level of air pollution should be expected in four years? 0.12 0.21 0.54 0.70 1.23 1.1 39. The volume, V, of a certain cone is given by 1.82 1.3 2.72 1.5 4.94 1.7 V(h) : 12 = 10.00 1.8 Using linear regression on the transformed data, the uptake rate can be approximated by Suppose the height is expressed as a function of time, t, by h(t) = 2t. a. Find the volume when t = 2. 1.95x f(x) = Graph this function against Express the volume as a function of elapsed time 1+0.95x
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