Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Question
2343456543234543Taco
![Step 2 of 5
Since the numerator is the derivative of the denominator, except for a constant factor, the substitution form of
the integrand is a du, where a is a constant factor.
Use the substitution u = cos (5x + 8)|
cos (5 x + 8)
Find du.
du = -5 sin( 5x +8)
-5 sin (5x + 8)| dx
Step 3 of 5
Substitute the expressions for u and for du to write t
tan(5x + 8)dx in terms of u.
sin(5x + 8) dx
cos(5x + 8)
tan(5x + 8)dx =
du](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fc8e65e40-3937-42b6-932f-bc2c992c9f03%2Fe3b70298-7894-4ca7-b6b6-a1fd757455d9%2F70slsb_processed.png&w=3840&q=75)
Transcribed Image Text:Step 2 of 5
Since the numerator is the derivative of the denominator, except for a constant factor, the substitution form of
the integrand is a du, where a is a constant factor.
Use the substitution u = cos (5x + 8)|
cos (5 x + 8)
Find du.
du = -5 sin( 5x +8)
-5 sin (5x + 8)| dx
Step 3 of 5
Substitute the expressions for u and for du to write t
tan(5x + 8)dx in terms of u.
sin(5x + 8) dx
cos(5x + 8)
tan(5x + 8)dx =
du
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