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Substitute A = 2, B =-2 and C = 10 in equation (1), 20# 2 (-2)+10 2 2+4)-14 #2+42+5 2 2+4 14 #2+42+5 20# That is Integrate on both sides, 2c+ 4 (x - 1) (22 4x 5) 14 (« + 2)2 + 1 + 14 tan-1( 2) +C 02 +42+5 20x Thus, 024,40+5 Therefore, the value of the integral is 20x 024,40+5

Substitute A = 2, B =-2 and C = 10 in equation (1), 20# 2 (-2)+10 2 2+4)-14 #2+42+5 2 2+4 14 #2+42+5 20# That is Integrate on both sides, 2c+ 4 (x - 1) (22 4x 5) 14 (« + 2)2 + 1 + 14 tan-1( 2) +C 02 +42+5 20x Thus, 024,40+5 Therefore, the value of the integral is 20x 024,40+5

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Question

Why does 2x-10 become 2x-4-14??????

Substitute A = 2, B =-2 and C = 10 in equation (1), 20# 2 (-2)+10 2 2+4)-14 #2+42+5 2 2+4 14 #2+42+5 20# That is Integrate on both sides, 2c+ 4 (x - 1) (22 4x 5) 14 (« + 2)2 + 1 + 14 tan-1( 2) +C 02 +42+5 20x Thus, 024,40+5 Therefore, the value of the integral is 20x 024,40+5
Transcribed Image Text:Substitute A = 2, B =-2 and C = 10 in equation (1), 20# 2 (-2)+10 2 2+4)-14 #2+42+5 2 2+4 14 #2+42+5 20# That is Integrate on both sides, 2c+ 4 (x - 1) (22 4x 5) 14 (« + 2)2 + 1 + 14 tan-1( 2) +C 02 +42+5 20x Thus, 024,40+5 Therefore, the value of the integral is 20x 024,40+5
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