Sub: Data structureConsider the following 'C’ routineint DO ( int a[ ], int /b, int ub){int temp;if( /b == ub)return a[lb];else{temp =DO( a, Ib+1, ub);if (a[/b]<= temp);return a[/b];elsereturn temp;}What does DO(a,0,5) return ifa[ ] = {0, –1,10,12,5,8};

The program has two parts: Calling function: It generally pass the value(s) to the called function…

Sub: Data structure Consider the following 'C' routine int DO ( int a[ ], int /b, int ub) { int temp; if( Ib == ub) return a[lb]; else { temp =DO( a, lb+1, ub); if (a[/b]<= temp); return a[lb]; else return temp; } } What does DO(a,0,5) return if a[ ] = {0, –1,10,12,5,8};

Sub: Data structure Consider the following 'C' routine int DO ( int a[ ], int /b, int ub) { int temp; if( Ib == ub) return a[lb]; else { temp =DO( a, lb+1, ub); if (a[/b]<= temp); return a[lb]; else return temp; } } What does DO(a,0,5) return if a[ ] = {0, –1,10,12,5,8};

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

See similar textbooks

Similar questions

#python def add_func(a,b): print(f"add_func output for 1 + 2: {add_func(1, 2)}") print(f"add_func output for good + day: {add_func('good',' day')}") (add_func(1,2) = 3, (add_func('good',' day') = "good day"
#include using namespace std; class fraction{ float d,s; public: fraction() { d=0; s=1; fraction(int a, int b) { d=%3; s=b3; } void print() { cout<
UML Design for Turing Machine Description: An electro-mechanical device used by the British cryptologists to help decipher German Enigma-machine-encrypted secret messages during World War II. A Turing Machine is a very simple abstract model of computation. The machine has an infinite tape that is divided into cells (or squares). Each cell contains a symbol (or character) chosen from some small set of possible symbols. Most of the cells are blank, that is, they contain the blank symbol. The number of non-blank cells is finite. The machine is located on one of the cells, and it can only "see" the symbol in the cell where it is located. It can write a new value to that cell. It can move left or right on the tape, one cell at a time. The machine is in one of a fixed, finite number of possible states. One of the states is the halt state. A Turing Machine has a table of rules. The table of rules is the program for the machine. A rule tells the machine what action to take when it is in a…
CFG: Example 1 • Draw the CFG for the following code: int f(int n){ } int m = n* n; if (n < 0) else return 0; return m;
4. Create the following getter methods a. Getter method for firstname (use ? getFirstnamel )). b. Getter method for lastname ( use ? getlastname() ). c. Getter method for userld ( use ? getUserld(O). d. Getter method for totalUsers (use ? getTotalUsers() ). www
C++ performing addition on complex data using class and object. should ask for real and imaginary part of two complex numbers, and display the real and imaginary parts of their sum output should be Complex number 1: 1+7i Complex number 2: 3+6i Sum of complex number: 4+13i
Solve in C Program Passing Structure as Parameters See Photo below for more details
37. #include int main() { int num = 5; printf(" The value of num is %d ", num ); What is printed?
main.cpp 1 @include 2 using namespace std; int maxResult() 4-( int maxVal = 0; 6. for (int i = 0; i <= n; i += a) { for (int j = e; j <= n i;j += b) !! 10 (float)(n - (i + j)) / (float)(c); 11 float z = 12 if (floor (z) { int x = i / a; int y 13 ceil(z)) 14 15 16 j/ b; max (maxVal, x + y + (int)z); 17 maxVal = 18 19 20 21 22 return maxVal; 23 } 24 int main() 26 { 25 27 28 cout << maxResult( ); 29 30 return 0; 31 } Input Compilation failed due to following erors) main.cpp:7:23: error: 'n was not declared in this scope 7 for (int i = 0; i <= n; i t a) main.cpp:7:31: error: 'a' was not declared in this scope 7 for (int i 0; i <= n; i t a) main.cpp:9:36: error: 'b' was not declared in this scope for (int j = 0; j <- n i; j b) %3D main.cpp:11:45: error: was not declared in this scope
C++ complete and create magical square #include <iostream> using namespace std; class Vec {public:Vec(){ }int size(){return this->sz;} int capacity(){return this->cap;} void reserve( int n ){// TODO:// (0) check the n should be > size, otherwise// ignore this action.if ( n > sz ){// (1) create a new int array which size is n// and get its addressint *newarr = new int[n];// (2) use for loop to copy the old array to the// new array // (3) update the variable to the new address // (4) delete old arraydelete[] oldarr; } } void push_back( int v ){// TODO: if ( sz == cap ){cap *= 2; reserve(cap);} // complete others } int at( int idx ){ } private:int *arr;int sz = 0;int cap = 0; }; int main(){Vec v;v.reserve(10);v.push_back(3);v.push_back(2);cout << v.size() << endl; // 2cout << v.capacity() << endl; // 10v.push_back(3);v.push_back(2);v.push_back(3);v.push_back(4);v.push_back(3);v.push_back(7);v.push_back(3);v.push_back(8);v.push_back(2);cout…
void exchangeByValue (int x, int y) { printf ("\n\nOriginal x and y received: $d $d", x, y); int temp; temp =x; x=y; y=temp; printf("\nNew: id $d", x, y): } void exchangeByRef (int *x, int *y) { printf ("\n\nOriginal x and y received: $d $d", *x, *y); int temp; temp = *x; *x = *y; *y = temp; printf ("\nNew: id $d", *x, *y); } а. Show the output b. Trace the output (show the tracing using drawing). Explain your answer if necessary.
C programming #include <stdio.h>int main() {int i, j, n ;printf("height? ") ;scanf("%2d", &n) ;for (i = 1 ; i <= n ; i++) {// printf("%d: ", i) ;for (j = 1 ; j <= i ; j++) {// Pick *one* of the following// printf("%d", j % 10) ;printf("*") ;}printf("\n") ;}return 0 ;} How can I get output like this by editing the given programming -- height? 5************************* and then how can I get the following?- height? 7 1 123 12345 1234567 123456789 12345678901 1234567890123