Styles Part I: Separation of Ammonium Chloride Mass of small evaporating dish Mass of small evaporating dish with sample Mass of original sample Mass of small evaporating dish after removing ammonium chloride Mass of ammonium chloride Percent of ammonium chloride (show calculations) Part II: Extraction of Salt From Sand Mass of small evaporating dish Mass of small evaporating dish with dry sand Mass of sand OC 41.621 g 42.928 g 8 Dictate Sensitivity Voice Sensitivity 41.621 g 43.642 g B 43.437 g %

Styles Part I: Separation of Ammonium Chloride Mass of small evaporating dish Mass of small evaporating dish with sample Mass of original sample Mass of small evaporating dish after removing ammonium chloride Mass of ammonium chloride Percent of ammonium chloride (show calculations) Part II: Extraction of Salt From Sand Mass of small evaporating dish Mass of small evaporating dish with dry sand Mass of sand OC 41.621 g 42.928 g 8 Dictate Sensitivity Voice Sensitivity 41.621 g 43.642 g B 43.437 g %

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Mass Aluminum Foil (g) 2.5415 Mass Filter Paper (g) 0.2777 Mass Filter Paper + Product (g) 35.6484 Mass Product (g) O 35.3708 g O 35.3705 g O 35.3707 g 35.3709 g O 35.3706 g Next
Remaining Time! 02:29:4. Consider the balanced chemical equations shown below. When a 6.00 g sample of a mixture of iron (Fe) and aluminum (Al) is treated with excess HCl(aq), 0.177 moles of H2 are obtained. What is the mass percentage of Fe in the original mixture? Choose the closest answer. Fe(s) + 2 HCI(aq) FeCl2(aq) - + H2(g) 2 Al(s) +6 HC((aq) 2 AICI3(aq) + 3 H2(g) 96 % 69 % 47 % 33 % 17 % Rack Question Menu - O O
If the mass of 0,8 moles mixtures of NO and CH4 gases is 17 grams; I. The number of moles of NO is greater than the number of moles of CH4.II. CH4 in the mix is 8 grams.III. NO in the mix is 0,3 mole. Which of the statements are corrrect? (H: 1, C:12, N: 14, O: 16) A) I, II B) I, III C) I, II, III D) II, III E) Only I
C6Н1206 602→ 6CO2 6H2O + Determine the following the number of grams of H2O produced from 270 grams of C6H1206 9, [Molar Masses (g/mole): C = 1 2; H = 1; O = 16] %D Oa. 162 grams H2O b. 27 grams H2O С. 18 grams H20 Od. 108 grams H20
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m/course.html?courseld=16481757&OpenVellumHMAC=feeaec83fa5cc7b2f32454414caf19a1#10001 Part C In the gaseous state, chlorine exists as a diatomic molecule Cl2 (Molar mass = 70.9 g/mol). Calculate the number of moles of chlorine present in 140 g of chlorine gas. Express the quantity in moles to three significant figures. • View Available Hint(s) ? mol Moles of chlorine gas = Submit Previous Answers X Incorrect; Try Again Multi-step problems A problem that asked you to convert molecules to grams could require two steps 1. convert the molecules to moles P Pearson 2convert to moles to areme Copyright O 2021 Pearson Education Inc. All rights reserved. I Terms of Use | Privacy Policy I Permissions | Contact Us |
7 Sodium azide (Na,N) decomposes on heating to form sodium and nitrogen gas. 2Na,N → 6Na + N2 1.35g of sodium nitride were heated. a Calculate the mass of sodium formed on complete decomposition of the sodium nitride. Give your answer to 3 significant figures. (AO2) 3 marks b Calculate the volume of nitrogen gas (in cm³) produced on complete decomposition of 1.35 g of sodium nitride at 320K and 110kPa. The gas constant R = 8.31JK-'mol-'. Give your answer to 3 significant figures. (AO2) 3 marks
n3 of 14 Phosphorus reacts with oxygen to form diphosphorus pentoxide, P,0,. 4 P(s) + 5 0,(g) - → 2 P,0,(s) How many grams of P,O, are formed when 3.83 g of phosphorus reacts with excess oxygen? Show the unit analysis used for the calculation by placing the correct components into the unit-factor slots. 言性料 E 3.83 g P × = g P,O, 自自 5. 2 .... 雪 Answer Bank 32.00 g O2 141.94 g P2O5 4 mol P 30.97 g P 1 mol P205 2 mol P205 1 mol O, 5 mol O2 1 mol P , , AT- rs .** r a s W, e | | contact us | help about us privacy policy terms of use careers MacBook Air
O 00 5 Phosphorus reacts with oxygen to form diphosphorus pentoxide, P,O,. 4 P(s) + 50,(g) –→ 2 P,0,(s) How many grams of P,O, are formed when 6.71 g of phosphorus reacts with excess oxygen? Show the unit analysis used for the calculation by placing the correct components into the unit-factor slots. 6.71 g P x = g P,O, Answer Bank 32.00 g 0, 4 mol P I mol P 30.97 g P 2 mol P,O, I mol P,0, I mol O, 141.94 g P,0, 5 mol 0, grams of P,0,: g P,0,
A mixture weighing 28.516g containers 4.518g NH4CL, 15.20g SiO2, with the remainder NaCl. find the percent, weight, of each component. Show you method for making the calculations.
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If your sample of antacid plus watchglass weighs 8.0756 g and the watchglass after transfer of the sample weighs 7.9615 g, what is the weight of antacid being used?