Study the equilibrium system. 2CO(g) + O2 (g) = 2CO2 (9) What will happen if the pressure on the system increases? O The quantity of CO2 (g) increases. The quantities in the system do not change. O The quantity of CO2 (g) decreases. The quantity of CO(g) increases.

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**Equilibrium System Analysis**

**Chemical Equation:**
\[ \text{2CO(g)} + \text{O}_2\text{(g)} \rightleftharpoons \text{2CO}_2\text{(g)} \]

**Question:**
What will happen if the pressure on the system increases?

**Answer Choices:**

- **The quantity of CO\(_2\) (g) increases.** (This option is highlighted, indicating it is the selected answer.)
- The quantities in the system do not change.
- The quantity of CO\(_2\) (g) decreases.
- The quantity of CO(g) increases.

**Explanation:**
The equilibrium involves gaseous reactants and products. According to Le Chatelier's Principle, increasing the pressure of the system will shift the equilibrium towards the side with fewer moles of gas. In this case, the reaction moves towards the production of CO\(_2\) (g), increasing its quantity, because it has fewer moles of gas on the product side (2 moles) compared to the reactant side (3 moles).
Transcribed Image Text:**Equilibrium System Analysis** **Chemical Equation:** \[ \text{2CO(g)} + \text{O}_2\text{(g)} \rightleftharpoons \text{2CO}_2\text{(g)} \] **Question:** What will happen if the pressure on the system increases? **Answer Choices:** - **The quantity of CO\(_2\) (g) increases.** (This option is highlighted, indicating it is the selected answer.) - The quantities in the system do not change. - The quantity of CO\(_2\) (g) decreases. - The quantity of CO(g) increases. **Explanation:** The equilibrium involves gaseous reactants and products. According to Le Chatelier's Principle, increasing the pressure of the system will shift the equilibrium towards the side with fewer moles of gas. In this case, the reaction moves towards the production of CO\(_2\) (g), increasing its quantity, because it has fewer moles of gas on the product side (2 moles) compared to the reactant side (3 moles).
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