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- I need help with all the partsI need the answer as soon as possibleYou are a researcher who wants to know what the mean (µ) level of anxiety would be for the whole population if they were all receiving a new anti-anxiety therapy. You can’t give the therapy to the whole population, so you give it to a sample, and you get M = 32.1 as the average anxiety level for the sample on the therapy. What is the reason that you can’t just simply assume that µ = 32.1? You didn’t use random assignment Sampling error Descriptive statistics Inferential statistics
- 4. (Exam 1 Summer 2020) Use the preamble below to answer the questions that follow An experiment to gain a better understanding of the role of various substances in melting ice was run in 2004 by Edinson Cavani, a researcher, in a certain lab in Memphis, TN. For each observation, a 10 ml block of ice was placed into water containing a given concentration of sugar, or salt, or a sugar and salt mix. The melting time for the ice block was measured in seconds and then converted to minutes. The three factors of interest were shape of ice block (lozenge, cylinder, and cube), solute (sugar, salt, and equal mix of sugar and salt), and concentration (5%, 10% 15%, 20%). (a) What is the response(outcome) variable for this study? Answer: (b) How many unique treatment combinations are there? Suppose there were two replicates per treatment combination, what is the total number of trials? i. Number of unique treatment combinations ii. Total number of trials Answer: Answer: (c) Would you say the…MORE BENEFITS OF EATING ORGANIC Using specific data, we find a significant difference in the proportion of fruit flies surviving after 13 days between those eating organic potatoes and those eating conventional (not organic) potatoes. This exercise asks you to conduct a hypothesis test using additional data. In this case, we are testing Họ : Po = Pc Ha: Po > Pc where p, and p. represent the proportion of fruit flies alive at the end of the given time frame of those eating organic food and those eating conventional food, respectively. Use a 5 % significance level. Effect of Organic Bananas After 25 Days After 25 days, the proportion of fruit flies eating organic bananas still alive is 0.45 , while the proportion still alive eating conventional bananas is 0.42. The standard error for the difference in proportions is 0.029. What is the value of the test statistic? Round your answer to two decimal places. z = i What is the p-value? Round your answer to three decimal places. p-value = What…Hi, i have one question. How was the level of significance obtained? at the beginning of the exercise it is clarified that it is (α)=0.05 but I don't know where this value comes from
- 5. Is ultrasound a reliable method for determining the gender of an unborn baby? The data on 100 births is given below. a. What is P(F)? Write your answer as a decimal. b. What is P(F|Pm)? Round your answer to 4 decimal places. c. True or False: F and Pm are independent. Write either TRUE or FALSEFind a recent journal article(peer reviewed scientific publication) in a field of interest to you which contains references to p-values. I will help you find an article if you want, tell me what you’re interested in. How large is the p-value? Do you think the results of this study are strong? How might they be stronger? Is there anything the authors should have included?For the situation described below, state the null and alternative hypotheses to be tested. (Enter != for ≠ as needed.) A new variety of pearl millet is expected to provide an increased yield over the variety presently in use, which has a mean yield of about 55 bushels per acre.
- 4. Do vaccines work? I take a sample of 1000 of unvaccinated people exposed outside and determined that 600 of them were infected with Comid-19. On the other hand, I take a sample of 800 people who are vaccinated against Comid- 19 and exposed outside and determined that 420 of them were infected with Comid-19. Using a = 0.06, test whether or not the rate of getting Comid-19 is higher in unvaccinated individuals compared to vaccinated ones.The chi-square test is appropriate for use when: you have data from two numerical variables. you have the dependent and independent variables need to be measured on an interval or ratio scale. you have data from two categorial variables. you have one categorical independent variable and one numerical scaled dependent variable.The calculations for a factorial experiment involving four levels of factor A, three levels of factor B, and three replications resulted in the following data: SST = 286, SSA = 26, SSB = 24, SSAB = 178. Set up the ANOVA table. (Round your values for mean squares and F to two decimal places, and your p-values to three decimal places.) Source Sum of Variation of Squares Factor A Factor B Interaction Error Total ONL Degrees of Freedom Mean Square F p-value Test for any significant main effects and any interaction effect. Use α = 0.05. Find the value of the test statistic for factor A. (Round your answer to two decimal places.) Find the p-value for factor A. (Round your answer to three decimal places.) p-value = State your conclusion about factor A. Because the p-value > a = 0.05, factor A is not significant. Because the p-value ≤ α = 0.05, factor A is significant. Because the p-value > a = 0.05, factor A is significant. Because the p-value ≤ α = 0.05, factor A is not significant.
