Student test scores are studied and it is believed the mean for all students is 100 with a standard deviation of 8.7 A normally distributed sample is taken to see if scores will be better than the general population testing at the .06 level. 114 92 111 104 121 99 108 110 130 98 97 102

Q: The Diabetic Association of Pakistan sampled 4900 severely overweight Pakistanis between 20 and 59…

A: Given,sample size(n)=4900sample proportion(p^)=0.171-p^=1-0.17=0.83α=1-0.95=0.05α2=0.025Z0.025=1.96…

Q: According to a simple random sample, 30 of 160 of workers said they didn’t get a promotion that they…

A:

Q: Express the confidence interval 0.222<p<0.888 in the form p±E.       p±E=(?)±(?)

A: Given that, 0.222&lt;p&lt;0.888 We have to express p±E form

Q: More carry-on bags for passengers on a flight can delay the loading and un-loading of passengers.…

A: Given:                              Number of favorable cases (X) = 172…

Q: A poll showed that 48 out of 120 randomly chosen graduates of AUAF work in the government. What is…

A: The confidence interval is calculated using the sample statistic, critical value and the standard…

Q: In a sample of 100 students, 30% said they use note-taking apps (like Notability, Goodnotes, etc.).…

A: Given that, In a sample of 100 students, 30% said they use note-taking apps. p^=30% = 0.30N = 10090%…

Q: A random sample of 5006 adults in a country includes 755 who do not use the Internet. Construct a…

A: Formula :

Q: A random sample of 300 of toy trains produced by a company are selected from a production line and…

A: Given Data: x=60 n=300 p^=xn=60300=0.2   z-value for 95% Confidence level: z=1.96

Q: What is the talpha/2 value to use for calculating a confidence interval from a sample of size 45…

A:

Q: A random sample found that forty percent of 100 Americans were satisfied with the gun control laws…

A: The objective of this question is to compute a 99% confidence interval for the true proportion of…

Q: country includes 754 who do not use the Internet. Construct a 95% confidence interval estimate of…

A:

Q: When 302 college students are randomly selected and surveyed, it is found that 122 own a car. What…

A: E have to find point estimate with with confidance interval..

Q: A survey of 80 recent fatal traffic accidents showed that 50 were alcohol-related.  Find the 84%…

A:

Q: Of 400 employees selected randomly from one company, 18.25% of them commute by carpooling. Construct…

A: The sample size n = 400. The probability p is 0.1825 The absolute value of Zα/2 is 1.96 using the…

Q: Find the 68% confidence interval for the percentage of leaky diapers with a sample of 100 diapers…

A: Let X be the number of defective diapers and n is the number of diapers. From the given information,…

Q: In simple random sample of 150 of workers, 22 said their work place environment is toxic. Construct…

A:

Q: In a plant box consisting of 120 seedlings, 80 seedlings were treated with growth enhancer. Compute…

A: Let X=80, n=120

Q: In a survey of 589 adults, 233 say they have started paying bills online in the last year. Construct…

A:

Q: A random sample of 5010 adults in a country includes 760 who do not use the Internet. Construct a…

A: Givensample size(n)=5010x=760sample proportion(p^)=xn=7605010≅0.1517Confidence level=95%

Q: Calculate 95% confidence intervals for the proportion of dwellings in this city that use oil for…

A: It is given that  Sample size = 1000 Favourable cases, X = 228 Sample proportion, p^ = 228/1000 =…

Q: He investigates how many of the printed newspapers are printed incorrectly. 35 out of 200 newspapers…

A: we have given that  sample size n=200 and favorable cases x=35 sample proportion p^=x/n

Q: Construct a confidence interval  n=135 x=74 95% confidence

A: Given: Sample size (n) = 135 and x = 74 Confidence level = 95%

Q: In a sample of 550 adults, 512 had children. Construct a 99% confidence interval for the true…

A: Given X=512 n=550

Q: A drug is used to help prevent blood clots in certain patients. In clinical trials, among 4990…

A: Solution: Let X be the number of patients developed the adverse reaction of nausea and n be number…

Q: In a sample of 86 recommendations, it is found that 60% of them made money. Determine the upper…

A: Given Data: The number of recommendations is: n=86 The confidence interval is: CI=95% The proportion…

Q: In a survey of 160 randomly selected gun owners, it was found that 80 of them said they owned a gun…

A: Sample size (n)=160  80 of them said they owned a gun primarily for protection  We have to find…

Q: Compute a confidence interval on the difference between means?

A:

Q: A random sample of 5008 adults in a country includes 760 who do not use the Internet. Construct a…

A: n=5008x=760

Q: If n=130 and ôp (p-hat) =0.93, find the margin of error at a 99% confidence level Give your answer…

A: Here, the margin of error for proportion p^ is to be calculated. The formula is given by, z*p^1-p^n,…

Q: Also compute 99% Confidence interval

A: We have, X¯1 = 7.5556,  s1 = 2.2973 , n1 = 9and,X2 = 11.3333, s2 = 2.1794, n1= 9 Also, pooled…

Q: Suppose that a garage finds that 42 customers of 142 customers samples get their oil changes on…

A: The objective of this question is to find the lower bound of the 98% confidence interval for the…

Q: Suppose that a garage finds that 42 customers of 142 customers samples get their oil changes on…

A: The objective of this question is to find the lower bound of the 98% confidence interval for the…

Q: Assume that 66 % of single women and 81.9 % of single men own cars. Also assume that these estimates…

A: Given that, p1= 66% = 0.66 p2= 81.9% = 0.819  And we know that, q1= (1-p1)= 1-0.66 = 0.34  q2=…

Q: A researcher surveys 722 randomly selected Australians and asks them: "Do you believe that Climate…

A: Given data Number of people answered yes x = 468 Sample size (n) = 722

Q: A study of 420,029 cell phone users found that 132 of them developed cancer of the brain or nervous…

A: From the provided information Confidence level = 95% Sample size (n) = 420029 132 of them developed…