Template Code:#include #include #define TOTAL_COURSE 3int main(void){ printf("Hello World!\n"); // You can delete this line. return 0;} Student Grade Mini-Database.Develop a program that will define and store a student record. The data will be entered by the user. Afterward, calculate and display the GPA of each student. You will needto use arrays with structureTemplate Code Intl Code GeHow to Calculate GPALeti-ith CourseUnita-Number of Units for Course iGrade - Final Grade for Course iTherGPA-ade,Fire faithSample Input ResultsSample InpuJohn10912345 degree: ECEECEPhysics100GeologyJose10854321CPEPhysics80Mathematics course 2 grade 7070Geology901|4John10912345ECEPhysic10070GeologysoMathematics course 2 grade 6060602Keology90。6₂John100hExpected Console OutputEnter number of students to record 2student name: JohnO number: 10912345p202⁰bcourse 1 name: Physicscourse 1 grade 100course 1 total unit 32 Mathematics course 2 grade 70course 2 name: MathematicsJosepse 1CPEPhysissoPGeology501course 2 total unit 2coursescourse 3 name GeMathematics course 2 grade: 60course 3 grade 50course 3 grade yocourse 3 total un nestudent name: Josenumber: 108543215degree: CPEdegreedthecourse 1 name: Physicscourse 1 grade 80course 1 total units: 3course 2 name: Mathematics502course 2 total unit: 2course 3 name: Geologycourse 3 grade: 90course 3 total unitsJohn with ID number 10912345 has a GPA of 81.667Jose with ID number 10854321 has a GPA of 75.000Enter number of students to record 1Enter number of students to record 2studentJOnumber: 10912345degree: ECEcourse name: Physics1course 1 grade: 100course 1 total units: 3D10912345 degree ECEECEECEDANcourse 2 total unit2enme Gcourse 3 grade: 50course 3 total units: 1student name: JoseO number: 10854321course total units: 3course 2 name MathematicsMutton 70course 2 grade 70degree CPEMondchcourse 1 name: Physiccourse 1 grade: 80course 1 total units:3course 2 name: Mathematicscourse 2 total units: 2course 3 name Geologycourse 3 grade: 90course 3 total units: 1John with ID number 10912345 has a GPA of 81.667Jose with ID number 10854321 has a GPA of 75.000Enter number of students to recordEnter number of students to record 2student name: JohnOnumber: 10912345course name: Physics1course 1 grade 100Jose10854321 degree CPECPEPhysics80course 2 total units: 2course 3 name: Geologycourse 3 grade 50course 3 total units: 1student name: JoseO number: 10854321course 1 name: Physicscourse 1 grade Ocourse 1 total unity 3course 2 name: MathematicsMathematics course 2 grade 60course 2 total units: 2course 3 name GeologyGeology course 3 grade 9090John with 10 number 10912345 has a GPA of 81.667Jose with ID number 10854321 has a GPA of 75.000Structure GuidelineThis subsection indicates the constraints on how you should design your data structuresStructure #1: CourseName TypeDescriptionname charStores the name of the course. Max Length of 80 charactersunitnt Stores the no. of units on the course.grade float Stores the grade of a student on the course.Structure #2: StudentNameTypeDescriptionStores the ID number of the student.dStores the name of the student. Max Length of 80 charactersname char80degreecharStores the degree program of the studentcourse Course TOTAL COURSE) Uses the Course Data Structure to store course contentCPA nostStores the grade of a student on the courseTesting Guideline:Make sure to use the TOTAL COURSE MACRO from your code. Please use it to define the number of courses per studentMake sure that the user can enter any value of value of N rom 0 to 20.000Hint:For you to get dynamically allocate the number of arrays of type Student, you can use the malloc function you've seen from your homework as shown belowStudent recordrecordnello stafwhere N is the number of students entered by the user

Code Header file #ifndef lab4_ex1_h #define lab4_ex1_h #define TOTAL_COURSE 3 #define BUFFER_SIZE 80…

Student Grade Mini-Database. Develop a program that will define and store a student record. The data will be entered by the user. Afterward, calculate and display the CPA of each student. You will need Template Code e Intl Code Ge How to Calculate GPA Let: Units,-Number of Units for Course i Grade,-Final Grade for Course i Ther GPA- Sample Input Results Sample Inpu John 10912345 degree: ECE JECE Physics 100 Geology 50 Jose 10854321 CPE Physics 80 5 770 Mathematics course 2 grade 70 70 course un 2 course 3 name Ge course 3 grade 50 course 3 grade 50 course 3 total un H 60 2 Geology 90 1 4 John 10912345 ECE Physic 100 70 12 Geology so Mathematics course 2 grade 60 100 o 60 2 Keology 90 o 2 John 10912345 ECE Fine Faith 100 h Expected Console Output Enter number of students to record 2 student name: John O number: 10912345 2e Mathematics course 2 grade 70 p course 1 name: Physics course 1 grade 100 course 1 total unit: 3 Geology 50 course 2 name: Mathematics h 0 student name: Jose Jose pose 1 CPE Physis 3 number: 10854321 degree: CPE depeche course 1 name: Physics course 1 grade 80 course 1 total units: 3 course 2 name: Mathematics 90 1 course 2 total unit: 2 counseren Mathematics course 2 grade: 60 course 3 name: Geology course 3 grade 90 course 3 total units John with ID number 10912345 has a GPA of 81.667 Jose with ID number 10854321 has a GPA of 75.000 Enter number of students to record 1 Enter number of students to record 2 student name: John Onumber: 10912345 degree: ECE course name: Physics 1 usega 100 course 1 total 3 Mathematics O number: 10912345 degree ECE course name: Physics 1 course 1 grade 100 course 1 total units: 3 course 2 name: Mathematics Mathematics course course 2 grade 70 course 2 total units: 2 20 course 3 name: Geology 2 course 2 total unit course 3 name G course 3 grade: 50 course 3 total units: 1 student name: Jose 10 number: 10854321 degree CPE mondon une 1 name: P course 1 grade: 80 course total units:3 1 course 2 name: Mathematics 50 course 3 grade 50 course 3 total units! student name student name: Jose 10 number: 10854321 Jose 10854321 degree CPE CPE course 1 name Physics Physics course 1 grade course 1 total unit 3 course 2 name Mathematics course 2 total units2 course 3 name Geology course 3 grade 90 course 3 total units 1 John with ID number 10912345 has a GPA of 81.667 ose with ID number 10854321 has a GPA of 75.000 Enter number of students to record Enter number of students to record 2 Mathematics course 2 grade 60 60 2 Geology course 3 grade: 90 course 3 total units John with ID number 10912345 has a GPA of 81.667 Jose with ID number 10854321 has a GPA of 75.000 course 2 total units: 2 course 3 name Geology Structure Guideline This subsection indicates the constraints on how you should design your data structures. Structure #1: Course Name Type Description name charStores the name of the course. Max Length of 80 characters unitnt Stores the no. of units on the course. grade float Stores the grade of a student on the course. Structure #2: Student Name Type Ga dint Description Stores the ID number of the student name chart801 Stores the name of the student. Max Length of 80 characters degree chart Stores the degree program of the student course Course TOTAL COURSEUses the Course Data Structure to store course content CPA nost Stores the grade of a student on the course recor Testing Guideline: Make sure to use the TOTAL COURSE MACRO from your code. Please use it to define the number of courses per student Make sure that the user can enter any value of value of N rom 0 to 20.000 Hint: For you to get dynamically allocate the number of arrays of type Student, you can use the malloc function you've seen from your homework as shown below record nello staf where N is the number of students entered by the user