Student A prepared a concentration cell (L) where the cathode half-cell uses an equilibrium solution of [PbBr4]² as the source of bromide ions. On the other hand, Student B prepared a galvanic cell (H), where the bromide ion concentration in the anode is equal to that in the cathode of cell L.

Student A prepared a concentration cell (L) where the cathode half-cell uses an equilibrium solution of [PbBr4]² as the source of bromide ions. On the other hand, Student B prepared a galvanic cell (H), where the bromide ion concentration in the anode is equal to that in the cathode of cell L.

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Concept explainers

Electrolysis

Electrolysis is defined as the process of breaking down ionic compounds into their constituent elements by passing a direct electric current through the compound in a fluid state. The cathode reduces cations, while the anode oxidizes anions. An electrolyte, electrodes, and some form of external power source are the main components required for conducting electrolysis. A partition, such as an ion-exchange membrane or a salt bridge, may also be used, but this is optional. These are primarily used to prevent the products from diffusing near the opposing electrode.

Question

Student A prepared a concentration cell (L) where the cathode half-cell uses an equilibrium solution of [PbBr4]²- as
the source of bromide ions. On the other hand, Student B prepared a galvanic cell (H), where the bromide ion
concentration in the anode is equal to that in the cathode of cell L.
Cell L
Pt(s) | Br21) | Br (ag) (1.0 M) || Br-(ag) (x M) from [PbBr4] (ag) Br2(1) | Pt(s)
Cell H
Pt(s) | Br21) | Br(ag) (x M) || BrO3(aq) (0.43 M), H*(ag) (1.00 M) | Br2) | Pt(s)
Given: Ereduction Br2(/Br-(ag) = 1.07 V

e) Make a Latimer Diagram of BrO3, Br2 and Br in this problem.

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