Stretching a spring farther before letting it bounce around will decrease the frequency of its oscillation O True False Moving to another question will save this response. Type he to search
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A: Using Hooke's law, F=-kx The force of gravity can be given by F=mg
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- A pendulum with a bob of a 100 g is initially displalaced from its iquililibrium position an release from a heigh of 63 cm above the equilibriums harmonic motion (SHM) without any energy loses to its surroundings. a- what is the the type of energy the pendulum possess at the point of release b-what happens to this type of energy as the bob starts moving toward the equilibriumA pendulum swings between extreme angles -a and a it relative to the equilibrium. As it passes through the point at the angle of a/2 w.r.t. the equilibrium, how is its instantaneous speed v related to the maximum speed of the oscillation?What is equal and opposite to the applied force on a spring? O equilibrium spring constant O displacement O spring force
- A car's 28.0 kg front tire is suspended by a spring with spring constant k = 1.45 x 10° N/m. At what minimum speed (in m/s) is the car moving if washboard bumps every 0.740 m drive the tire into a resonant oscillation? HINT m/s Need Help? Read It Watch It 1200 PM 19% 71°F Polluted air 105 11/28/2021 P Type here to searchA spring stretches 4.0-cm when a 7-g object is hung from it. The object is replaced with a block of mass 21 g that oscillates in simple harmonic motion. Calculate the period of motion.sThe kinetic energy of motion in a simple harmonic oscillating system is? (choose one option below) a) maximum as it passes the equilibrium point b) zero when it passes the equilibrium point c) a maximum when it reaches the maximum displacement d) both A and C e) both A and B
- A uniform rod of length L is supported by a ball-and-socket joint at A and by a vertical wire CD Derive an expression for the period of oscillation of the rod if end B is given a small horizontal displacement and then released.IT WAS FOUND WHEN BOBBING FOR APPLES THAT A WHOLE CYCLE FOR BOBBING = 0.7 SECONDS INITIALLY DISPLACED BY IF THE APPLE WAS 10.03m-FIND THE FOLLOWING: GIVEN: PERIOD OF OSCILLATION OF APPLES = 0.1 SECONDS FREQUENCY OF OSCILLATION OF APPLES: 1.428 Hz ANGULAR FREQUENCY = 8.97 rad/s FIND: AMPLITUDE OF POSITION OF APPLE AFTER 5 SECONDS VELOCITY OF APPLE AFTER 5 SECONDS. ACCELERATION OF APPLE AFTER 5 SECONDS OSCILLATION = m m m/s m/s2A spring stretches 3.9-cm when a 13-g object is hung from it. The object is replaced with a block of mass 22 g that oscillates in simple harmonic motion. Calculate the period of motion. s