STRATEGY This problem can be solved by substituting values into Bernoulli's equation to find the pressure difference between the air under the wing and the air over the wing, followed by applying Newton's second law to find the mass the airplane can lift. SOLUTION Apply Bernoulli's equation to the air P, + V½pv,² = P, + V½pv,² flowing under the wing (point 1) and over the wing (point 2). Gravitational potential energy terms are small compared with the other terms, and can be neglected. Solve this equation for the pressure AP = P, - P2 = V½pv,² - V2pv,? = V½p(v2² - v,²) %3D 1 %3D difference. Substitute the given speeds and Ap = ½(1.29 kg/m³)(2452 m²/s² - 2222 m2/s²) p = 1.29 kg/m3, the density of air. AP = 6.93 × 10° Pa Apply Newton's second law. To support the plane's weight, the sum of the lift and gravity forces must equal zero. 2AAP -mg = 0-m = 5.66 x 10 kg Solve for the mass m of the plane.
Fluid Pressure
The term fluid pressure is coined as, the measurement of the force per unit area of a given surface of a closed container. It is a branch of physics that helps to study the properties of fluid under various conditions of force.
Gauge Pressure
Pressure is the physical force acting per unit area on a body; the applied force is perpendicular to the surface of the object per unit area. The air around us at sea level exerts a pressure (atmospheric pressure) of about 14.7 psi but this doesn’t seem to bother anyone as the bodily fluids are constantly pushing outwards with the same force but if one swims down into the ocean a few feet below the surface one can notice the difference, there is increased pressure on the eardrum, this is due to an increase in hydrostatic pressure.
![EXAMPLE 9.15
Lift on an Airfoil
GOAL Use Bernoulli's equation to calculate the lift on an airplane wing.
PROBLEM An airplane has wings, each with area 4.00 m², designed so that air flows over the top of the
wing at 245 m/s and underneath the wing at 222 m/s. Find the mass of the airplane such that the lift on
the plane will support its weight, assuming the force from the pressure difference across the wings is
directed straight upwards.
STRATEGY This problem can be solved by substituting values into Bernoulli's equation to find the
pressure difference between the air under the wing and the air over the wing, followed by applying
Newton's second law to find the mass the airplane can lift.
SOLUTION
Apply Bernoulli's equation to the air
P,+ Vapv,² = P2 + V½pv,?
flowing under the wing (point 1) and
over the wing (point 2). Gravitational
potential energy terms are small
compared with the other terms, and
can be neglected.
Solve this equation for the pressure
AP = P1 - P2 = V½pv,² - V½pv,? = V½p(v,² - v,²)
difference.
Substitute the given speeds and
Ap = ½(1.29 kg/m³)(245² m²/s² - 2222 m2/s?)
p = 1.29 kg/m³, the density of air.
AP = 6.93 x 10' Pa
Apply Newton's second law. To support
2AAP -mg = 0 - m = 5.66 x 10° kg
the plane's weight, the sum of the lift
and gravity forces must equal zero.
Solve for the mass m of the plane.
LEARN MORE
REMARKS Note the factor of two in the last equation, needed because the airplane has two wings. The
density of the atmosphere drops steadily with increasing height, reducing the lift. As a result, all aircraft
have a maximum operating altitude.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F10109699-e850-457b-a56b-e064ba192cdf%2F3133f471-1fa3-402e-94c6-c6a979915bbb%2Fp422xhc_processed.jpeg&w=3840&q=75)
![PRACTICE IT
Use the worked example above to help vou solve this problem. An airplane has wings, each with area
4.10 m2, designed so that air flows over the top of the wing at 243 m/s and underneath the wing at
225 m/s. Find the mass of the airplane such that the VIlon the plane will support its weight, assuming the
force from the pressure difference across the wings is directed straight upwards.
kg
EXERCISE
HINTS: GETTING STARTED | I'M STUCK!
Approximately what size wings would an aircraft need on Mars if its engine generates the same differences
in speed as in the "Practice It" and the total mass of the craft is 450 kg? The density of air on the surface
of Mars is approximately one percent Earth's density at sea level, and theacceleration of gravity on the
surface of Mars is about 3.8 m/s.
m2](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F10109699-e850-457b-a56b-e064ba192cdf%2F3133f471-1fa3-402e-94c6-c6a979915bbb%2Fdwesnd_processed.jpeg&w=3840&q=75)
![](/static/compass_v2/shared-icons/check-mark.png)
Step by step
Solved in 4 steps with 3 images
![Blurred answer](/static/compass_v2/solution-images/blurred-answer.jpg)
![College Physics](https://www.bartleby.com/isbn_cover_images/9781305952300/9781305952300_smallCoverImage.gif)
![University Physics (14th Edition)](https://www.bartleby.com/isbn_cover_images/9780133969290/9780133969290_smallCoverImage.gif)
![Introduction To Quantum Mechanics](https://www.bartleby.com/isbn_cover_images/9781107189638/9781107189638_smallCoverImage.jpg)
![College Physics](https://www.bartleby.com/isbn_cover_images/9781305952300/9781305952300_smallCoverImage.gif)
![University Physics (14th Edition)](https://www.bartleby.com/isbn_cover_images/9780133969290/9780133969290_smallCoverImage.gif)
![Introduction To Quantum Mechanics](https://www.bartleby.com/isbn_cover_images/9781107189638/9781107189638_smallCoverImage.jpg)
![Physics for Scientists and Engineers](https://www.bartleby.com/isbn_cover_images/9781337553278/9781337553278_smallCoverImage.gif)
![Lecture- Tutorials for Introductory Astronomy](https://www.bartleby.com/isbn_cover_images/9780321820464/9780321820464_smallCoverImage.gif)
![College Physics: A Strategic Approach (4th Editio…](https://www.bartleby.com/isbn_cover_images/9780134609034/9780134609034_smallCoverImage.gif)