Story A ball is dropped from a height of feet. Each bounce is% of the height of the previous bounce. Equation f(x) = 12(0.75)*

Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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Story
A ball is dropped from a height of.
the height of the previous bounce.
Graph
Height
15
15 14 13 12 11 10
8
7
6
5
4
3
DROPPING THE BALL
2
1
0
feet. Each bounce is % of
Bounce Measurements
0 1 2 3 4 5 6 7 8 9
Bounce
Growth or Decay?
10
Rise over Run
Equation
f(x) = 12(0.75)*
Table of Values
X
0
1
2
3
4
5
6
Think about it
How high is first bounce?
y
Which is the first bounce less than 1 foot?
According to this model, when will the ball
stop bouncing?
Transcribed Image Text:Story A ball is dropped from a height of. the height of the previous bounce. Graph Height 15 15 14 13 12 11 10 8 7 6 5 4 3 DROPPING THE BALL 2 1 0 feet. Each bounce is % of Bounce Measurements 0 1 2 3 4 5 6 7 8 9 Bounce Growth or Decay? 10 Rise over Run Equation f(x) = 12(0.75)* Table of Values X 0 1 2 3 4 5 6 Think about it How high is first bounce? y Which is the first bounce less than 1 foot? According to this model, when will the ball stop bouncing?
Story
At Green Lake, the population of frogs is currently 360. It is expected to
increase 10% each year.
Graph
Frog Population
1000
900
800
700
600
500
400
300
200
100
0
0 1
FROG POPULATION
2
Green Lake Frogs
3 4 5 6 7 8 9
Years from Now
Growth or Decay?
10
Rise over Run
Equation
f(x) =
Table of Values
X
0
1
2
3
4
5
6
y
Think about it
What will the frog population be 4 years from
now?
When will the frog population reach 1000?
What is the change in the frog population
between now and 5 years from now?
Transcribed Image Text:Story At Green Lake, the population of frogs is currently 360. It is expected to increase 10% each year. Graph Frog Population 1000 900 800 700 600 500 400 300 200 100 0 0 1 FROG POPULATION 2 Green Lake Frogs 3 4 5 6 7 8 9 Years from Now Growth or Decay? 10 Rise over Run Equation f(x) = Table of Values X 0 1 2 3 4 5 6 y Think about it What will the frog population be 4 years from now? When will the frog population reach 1000? What is the change in the frog population between now and 5 years from now?
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