**Step 1**: The following code copies a string from source to target:```assembly.data source BYTE "This is the source string",0 target BYTE SIZEOF source DUP(0).code mov esi,0 ; index register mov ecx,SIZEOF source ; loop counterL1: mov al,source[esi] ; get char from source mov target[esi],al ; store it in the target inc esi ; move to next character loop L1 ; repeat for entire string mov edx, OFFSET source call WriteString mov edx, OFFSET target call WriteString```**Explanation**: - The code initializes a `source` string and a `target` location to store the copied string.- The `esi` register is used as an index to iterate through each character of the `source`.- For each iteration, the current character from `source` is stored in the `target`.- A loop (`L1`) ensures this operation continues until the entire string is copied.- After copying, a subroutine `WriteString` is called to output both `source` and `target`.**Task**: Rewrite the program using indirect addressing rather than indexed addressing.

Assembly Language: Low-level programming languages like assembly languages are created to interact directly with the hardware of a computer. Assembly languages are intended for human reading, as opposed to machine language, which uses binary and hexadecimal letters.Answer: Step 1. Assembly code: mov bx, Source mov dx, target mov ecx, SIZE OF Source. L1 : mov al, [bx] mov [dx], al. inc bx. inc dx. loop l1.

Engineering

Computer Science

Step1. The following code copies a string from source to target: .data source BYTE "This is the source string",0 target BYTE SIZEOF source DUP (0) .code L1: mov esi, 0 mov ecx SIZEOF source mov mov target at source[esi] target[si], al inc esi loop L1 Imov edx, OFFSET source call WriteString moved, OFFSET target call WriteString ; index register ; loop counter ; get char from source ; store it in the ; move to next character ; repeat for entire string Rewrite the program using indirect addressing rather than indexed addressing.

Step1. The following code copies a string from source to target: .data source BYTE "This is the source string",0 target BYTE SIZEOF source DUP (0) .code L1: mov esi, 0 mov ecx SIZEOF source mov mov target at source[esi] target[si], al inc esi loop L1 Imov edx, OFFSET source call WriteString moved, OFFSET target call WriteString ; index register ; loop counter ; get char from source ; store it in the ; move to next character ; repeat for entire string Rewrite the program using indirect addressing rather than indexed addressing.

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Question

**Step 1**: The following code copies a string from source to target:

```assembly
.data
source BYTE "This is the source string",0
target BYTE SIZEOF source DUP(0)
.code
mov esi,0 ; index register
mov ecx,SIZEOF source ; loop counter
L1:
mov al,source[esi] ; get char from source
mov target[esi],al ; store it in the target
inc esi ; move to next character
loop L1 ; repeat for entire string

mov edx, OFFSET source
call WriteString
mov edx, OFFSET target
call WriteString
```

**Explanation**:
- The code initializes a `source` string and a `target` location to store the copied string.
- The `esi` register is used as an index to iterate through each character of the `source`.
- For each iteration, the current character from `source` is stored in the `target`.
- A loop (`L1`) ensures this operation continues until the entire string is copied.
- After copying, a subroutine `WriteString` is called to output both `source` and `target`.

**Task**: Rewrite the program using indirect addressing rather than indexed addressing.

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