Step 5: Substitute v, = 0, cancel the 0 + gy, -v? + gy, mass m, and solve for v,. v, = V 2g(y, – Y) = V 2(9.80 m/s?)(10.0 m – 5.00 m) Vr = 9.90 m/s (B) Find the diver's speed at the water's surface, y = 0. Use the same procedure as in part (a), 0 + mgy, =mv? + o v - V 2gy, - V 2(9.80 m/s?)(10.0 m) = 14.0 m/s taking y,= 0. LEARN MORE
Step 5: Substitute v, = 0, cancel the 0 + gy, -v? + gy, mass m, and solve for v,. v, = V 2g(y, – Y) = V 2(9.80 m/s?)(10.0 m – 5.00 m) Vr = 9.90 m/s (B) Find the diver's speed at the water's surface, y = 0. Use the same procedure as in part (a), 0 + mgy, =mv? + o v - V 2gy, - V 2(9.80 m/s?)(10.0 m) = 14.0 m/s taking y,= 0. LEARN MORE
Step 5: Substitute v, = 0, cancel the 0 + gy, -v? + gy, mass m, and solve for v,. v, = V 2g(y, – Y) = V 2(9.80 m/s?)(10.0 m – 5.00 m) Vr = 9.90 m/s (B) Find the diver's speed at the water's surface, y = 0. Use the same procedure as in part (a), 0 + mgy, =mv? + o v - V 2gy, - V 2(9.80 m/s?)(10.0 m) = 14.0 m/s taking y,= 0. LEARN MORE
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