Step 4: Finding.your + C. Now that we have found our general solution and the "g(y)". we can finish up the problem by finding the "+ C". Given the following differential equation [6x? - y + 3] dx + [3y2 - x - 2] dy = 0 Which has an "E" and "g(y)" of F = 2x3 - yx + 3x + g (y) and 8(y) = y3 - 2y + C This gives us a general solution of 2x3 - yx + 3x + y3 - 2y = k Think of the "k" as the "+ C", we just moved it to the other side. Use the initial condition " y(0) = 8 " to find "k" and thus the specific solution for the problem. (A) 2x3 - yx + 3x + y3 - 2y = - 4 B) 2x3 - yx + 3x + y3 - 2y = 1048 2x - yx + 3x + y - 2y = 496 D 2x3 - yx + 3x + y3 - 2y = 8 E 2x3 - yx + 3x + y - 2y = 0

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