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Step 4 After integration by parts we have Je e38 cos(48) de = c || Submit Skip (you cannot come back) J e38 sin(40) de.

Step 4 After integration by parts we have Je e38 cos(48) de = c || Submit Skip (you cannot come back) J e38 sin(40) de.

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Please how do we find step 4
Step 3 We'll now apply the integration by parts procedure to the new integral Then dU = Step 4 After integration by parts we have [e³ Submit 4(-sin (40)) Submit Answer 2. [2/2 Points] e38 cos(40) de = || Need Help? Read It Skip (you cannot come back) DETAILS -4 sin(40) Viewing Saved Work Revert to Last Response Evaluate the integral. de and V = PREVIOUS ANSWERS 1.x e30 cos(40) de, letting U = cos(40) and dV = e3E 30 3 e30 sin(40) de. SCALCET9 7.1.032. 30 3
Transcribed Image Text:Step 3 We'll now apply the integration by parts procedure to the new integral Then dU = Step 4 After integration by parts we have [e³ Submit 4(-sin (40)) Submit Answer 2. [2/2 Points] e38 cos(40) de = || Need Help? Read It Skip (you cannot come back) DETAILS -4 sin(40) Viewing Saved Work Revert to Last Response Evaluate the integral. de and V = PREVIOUS ANSWERS 1.x e30 cos(40) de, letting U = cos(40) and dV = e3E 30 3 e30 sin(40) de. SCALCET9 7.1.032. 30 3
Evaluate the integral. Step 1 We will begin by letting u = sin(40) and dv = e30 de. fe e38 sin(40) de Then du = Step 3 Step 2 After integration by parts we have 30 4 cos (40) Then dU = Step 4 e30 sin(40) de = 30 4 cos(40) de and v = 4(-sin (40)) sin (40) 3 1 3 -4 sin(40) 30 e 3 30 sin(40) de and V = We'll now apply the integration by parts procedure to the new integral 1₁ e36 cos(40) de, letting U = cos(40) and dV = e³8 de. 30 4/3 3 | 30 3 4/3 30 e30 cos(40) de. 3
Transcribed Image Text:Evaluate the integral. Step 1 We will begin by letting u = sin(40) and dv = e30 de. fe e38 sin(40) de Then du = Step 3 Step 2 After integration by parts we have 30 4 cos (40) Then dU = Step 4 e30 sin(40) de = 30 4 cos(40) de and v = 4(-sin (40)) sin (40) 3 1 3 -4 sin(40) 30 e 3 30 sin(40) de and V = We'll now apply the integration by parts procedure to the new integral 1₁ e36 cos(40) de, letting U = cos(40) and dV = e³8 de. 30 4/3 3 | 30 3 4/3 30 e30 cos(40) de. 3
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