Step 2a: Use dimensional analysis to determine the theoretical yield of the product. Calculate the theoretical yield in grams Al:Os from the complete reaction of 64.7 grams Al according to the following balanced chemical equation: 2 Al(s) + Fe:O:(s) → Al:Os(s) + 2 Fe(s) STARTING AMOUNT

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Can someone help walk me through this conversion like its listed in the question? I think im getting the correct answer, but im getting the conversion wrong 

Step 2a: Use dimensional analysis to determine the theoretical yield of the product.
Calculate the theoretical yield in grams Al2Os from the complete reaction of 64.7
grams Al according to the following balanced chemical equation:
2
Al(s) + Fe:O:(s)→ Al:O:(s) +
2
Fe(s)
STARTING AMOUNT
ADD FACTOR
ANSWER
RESET
*( )
1
1.20
489
26.98
64.7
2
2.40
122.3
34.2
244.5
191
101.96
g/mol Al
mol Al
g Al:Os
mol Al2O3
g Al
g/mol Al:O3
Transcribed Image Text:Step 2a: Use dimensional analysis to determine the theoretical yield of the product. Calculate the theoretical yield in grams Al2Os from the complete reaction of 64.7 grams Al according to the following balanced chemical equation: 2 Al(s) + Fe:O:(s)→ Al:O:(s) + 2 Fe(s) STARTING AMOUNT ADD FACTOR ANSWER RESET *( ) 1 1.20 489 26.98 64.7 2 2.40 122.3 34.2 244.5 191 101.96 g/mol Al mol Al g Al:Os mol Al2O3 g Al g/mol Al:O3
Expert Solution
Step 1

Recall the given reaction

2Als + Fe2O3s  Al2O3s + 2Fes

We have to determine theoretical yield of product Al2O3 when 64.7 g of Al is reacted according to the given chemical equation.

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