Step 2 using the value from equation (i) 3(2p+1-VAp+1) < 1 2p 6p+3–3 /4p+1 < 1 2p subtract 1 both sides бр+3-34р+1 -1 <1- 1 2p 4p+3–3 /4p+1 < 0 2p now, for p > 0 we have 4p + 1 + 2 – 3 V4p + 1 < 0 = 4p + 1 - V4p + 1 – 2/4p + 1 + 2 < 0 V4p + 1 (V4p +1 – 1) – 2 (V4p + 1 – 1) < 0 > (V4p + 1 – 1) (V4p + I – 2) < 0

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