Step 2 using the value from equation (i) 3(2p+1-VAp+1) < 1 2p 6p+3–3 /4p+1 < 1 2p subtract 1 both sides бр+3-34р+1 -1 <1- 1 2p 4p+3–3 /4p+1 < 0 2p now, for p > 0 we have 4p + 1 + 2 – 3 V4p + 1 < 0 = 4p + 1 - V4p + 1 – 2/4p + 1 + 2 < 0 V4p + 1 (V4p +1 – 1) – 2 (V4p + 1 – 1) < 0 > (V4p + 1 – 1) (V4p + I – 2) < 0
Step 2 using the value from equation (i) 3(2p+1-VAp+1) < 1 2p 6p+3–3 /4p+1 < 1 2p subtract 1 both sides бр+3-34р+1 -1 <1- 1 2p 4p+3–3 /4p+1 < 0 2p now, for p > 0 we have 4p + 1 + 2 – 3 V4p + 1 < 0 = 4p + 1 - V4p + 1 – 2/4p + 1 + 2 < 0 V4p + 1 (V4p +1 – 1) – 2 (V4p + 1 – 1) < 0 > (V4p + 1 – 1) (V4p + I – 2) < 0
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Question
Explain the steps of determine red
Transcribed Image Text:Math / Advanced Math / Q&A Library / y2 2p Thus |g1|+ |92|+ ...
y2 2p Thus g1|+ |92|+ laml 3p <1, ... %3D ...
Step 2
using the value from equation (i)
3(2p+1-V4p+1)
< 1
2p
6p+3–3 4p+1
< 1
2p
subtract 1 both sides
бр+3-3 4р+1
- 1 < 1 – 1
2p
4p+3–3 /4p+1
< 0
2p
now, for p > 0
we have
4p + 1+ 2 – 3 V4p + 1 < 0
→ 4p + 1 – V4p + 1 – 2 /4p + 1 + 2 < 0
V4p + 1 (V4p + 1 – 1) – 2 (V4p +1– 1) < 0
→ (V4p + 1 – 1)(V4p + 1 – 2) < 0
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