Step 2: After Step 1 we examine the problem till we are confident with a plan for finding the unknown. I plan tofind everything by three laws. It may not be necessary to find everything, if we consider the only unknown is V,but for illustration, I shall find everything anyway.By KCL:At Node (3+V13i1-iz +1 A10 Ω1 A+At Node (4 i3 = İ2 + 1 A20|i.V2işIt is obvious that iz-iş = i1(Is it to you?)V3+22024By KVL:Take a loop from 3 back to 3 via: 3-4-2-1-3:Vz+V3-V,+V1= 0Another loop from 3 to 4 via V, back to 3 viaV2:V4- V2 = 0You may want to take another loop as thefirst but from 3 to 4 via V4. Try it and see thatit can be derived from the two equations13%3DNext we write the conditions on these unknownsusing the laws.By Ohm's law:V1 = i,x 10; V2= i2x 2; V3 = i3x 20; V4 = (1 A) x 10 ohmsabove.

Answered: Image /qna-images/answer/6cbed5c4-11f3-4225-9bd2-517f2f3e2838.jpg

Step 2: After Step 1 we examine the problem till we are confident with a plan for finding the unknown. I plan to find everything by three laws. It may not be necessary to find everything, if we consider the only unknown is V, but for illustration, I shall find everything anyway. . Вy KCL: 3 At Node 3 i1-İ2 +1 A 10 Ω 1 A + At Node O i3-İ2 + 1 A is It is obvious that i3- iş = i1 (Is it to you?) 2 202 4 By KVL: Take a loop from 3 back to 3 via: 3-4-2-1-3: Vz+V3-V,+V1= 0 Another loop from 3 to 4 via V, back to 3 via V2: V4-V2 = 0 You may want to take another loop as the first but from 3 to 4 via V4. Try it and see that it can be derived from the two equations Next we write the conditions on these unknowns using the laws. By Ohm's law: V1= i,x 10; V2 = izx 2; V3 = i3x 20; V4= (1 A) x 10 ohms %3D above.

Step 2: After Step 1 we examine the problem till we are confident with a plan for finding the unknown. I plan to find everything by three laws. It may not be necessary to find everything, if we consider the only unknown is V, but for illustration, I shall find everything anyway. . Вy KCL: 3 At Node 3 i1-İ2 +1 A 10 Ω 1 A + At Node O i3-İ2 + 1 A is It is obvious that i3- iş = i1 (Is it to you?) 2 202 4 By KVL: Take a loop from 3 back to 3 via: 3-4-2-1-3: Vz+V3-V,+V1= 0 Another loop from 3 to 4 via V, back to 3 via V2: V4-V2 = 0 You may want to take another loop as the first but from 3 to 4 via V4. Try it and see that it can be derived from the two equations Next we write the conditions on these unknowns using the laws. By Ohm's law: V1= i,x 10; V2 = izx 2; V3 = i3x 20; V4= (1 A) x 10 ohms %3D above.

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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