Step 1: Given: specific gravity, G=1.7 The objective is to determine: a. density of fluid in slug/ft³ b. specific weight in lbf/ft³

Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
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Please could you provide me with More details. and different answer if is that possible?

 

 
Step 1: Given:
specific gravity, G=1.7
The objective is to determine:
a. density of fluid in slug/ft³
b. specific weight in lbf/ft³
Step 2: Determining density in slug/ft3
We know,
G=
density of liquid
density of water
Pliquid
1000 kg/m³
⇒Pliquid = 1700 kg/m³
Now, 1 kg/m³ = 0.00194032 slug/ft³
⇒Pliquid = 1700×0.00194032
⇒Pliquid
= 3.298 slug/f
⇒1.7=
Pliquid
Pwater
Step 3: Determining specific weight in lbf/ft3:
1 kg/m³ = 0.06243 lb/ft³
→ specific weight in lbf/ft³= 1700x 0.06243 lb/ft³
= 106.13 lb/ft²³
Solution
a) Piquila = 3.298 slug/ft³
b) in lbf/ft³ = 106.13 lb/ft³
Transcribed Image Text:Step 1: Given: specific gravity, G=1.7 The objective is to determine: a. density of fluid in slug/ft³ b. specific weight in lbf/ft³ Step 2: Determining density in slug/ft3 We know, G= density of liquid density of water Pliquid 1000 kg/m³ ⇒Pliquid = 1700 kg/m³ Now, 1 kg/m³ = 0.00194032 slug/ft³ ⇒Pliquid = 1700×0.00194032 ⇒Pliquid = 3.298 slug/f ⇒1.7= Pliquid Pwater Step 3: Determining specific weight in lbf/ft3: 1 kg/m³ = 0.06243 lb/ft³ → specific weight in lbf/ft³= 1700x 0.06243 lb/ft³ = 106.13 lb/ft²³ Solution a) Piquila = 3.298 slug/ft³ b) in lbf/ft³ = 106.13 lb/ft³
5.G.
3 If a liguid has a 56 of 17
(a) What is the devrsty in Slayf fit ?
Slug
specific weight in Lbf?
(b) What is the specific weight
Transcribed Image Text:5.G. 3 If a liguid has a 56 of 17 (a) What is the devrsty in Slayf fit ? Slug specific weight in Lbf? (b) What is the specific weight
Expert Solution
Step 1: Given data

Specific gravity G = 1.7

Find

(1) Density ρ

(2) specific weight ɣ

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