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Steel, Brass, and Copper rods are connected as shown in the figure. Initially, the temperature was 15 degrees Celsius and the stress on the bars is zero. Eventually, the temperature increased to 25 degrees Celsius. Determine the total deformation on the steel. Steel Brass Copper Ecu = 120 GPa 17(10-)/°C Est = 200 GPa Ebr =100 GPa %3D 12(10-6)/°C apr = 21(10-6)/°C acu %3D ast Acu = 515 mm² Ast = 200 mm² Abr = 450 mm? %3D 300 mm- --200 mm 100 mm O -0.0058mm O 0.0165mm

Steel, Brass, and Copper rods are connected as shown in the figure. Initially, the temperature was 15 degrees Celsius and the stress on the bars is zero. Eventually, the temperature increased to 25 degrees Celsius. Determine the total deformation on the steel. Steel Brass Copper Ecu = 120 GPa 17(10-)/°C Est = 200 GPa Ebr =100 GPa %3D 12(10-6)/°C apr = 21(10-6)/°C acu %3D ast Acu = 515 mm² Ast = 200 mm² Abr = 450 mm? %3D 300 mm- --200 mm 100 mm O -0.0058mm O 0.0165mm

Structural Analysis
Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Steel, Brass, and Copper rods are connected as shown in the figure. Initially, the temperature was 15 degrees Celsius and the stress on the bars is zero. Eventually, the temperature increased to 25 degrees Celsius. Determine the total deformation on the steel. Steel Brass Copper Est = 200 GPa Ebr = 100 GPa Ecu = 120 GPa %3D ast = 12(10-6)/°C abr = 21(10¬6)/°C acu = 17(10-)/°C %3D Acu = 515 mm² |Ast = 200 mm? Abr = 450 mm² %3D 300 mm- 200 mm 100 mm O -0.0058mm O 0.0165mm O -0.0165mm O 0.0058mm
Transcribed Image Text:Steel, Brass, and Copper rods are connected as shown in the figure. Initially, the temperature was 15 degrees Celsius and the stress on the bars is zero. Eventually, the temperature increased to 25 degrees Celsius. Determine the total deformation on the steel. Steel Brass Copper Est = 200 GPa Ebr = 100 GPa Ecu = 120 GPa %3D ast = 12(10-6)/°C abr = 21(10¬6)/°C acu = 17(10-)/°C %3D Acu = 515 mm² |Ast = 200 mm? Abr = 450 mm² %3D 300 mm- 200 mm 100 mm O -0.0058mm O 0.0165mm O -0.0165mm O 0.0058mm
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