Steam undergoes an Isentropic process where it is initially at 1.05 MPa and 304C. The isentropic process causes its pressure to drop to 30 kPa. Find the tsat2, dryness, and enthalpy change. (69.10C, 90.4%, -657.34 kJ/kg) LO (179.91) 1.05 (182.04) (L Sat.) 10 v 10 194.44 2583.6 2778.1 6.5865 185.60 2585.I 2780.0 6.5696 Sat. 150 179.07 2532.0 2711 6.4342 182 29 2542.9 2725.1 6.4669 183.43 2553.4 2738.9 6.4984 188 50 25638 2752.3 6.3289 155 160 175.66 2550 0 2734.5 6.4678 165 178.64 2560.6 2748 2 6.4989 170 172.60 2539.2 2720.4 6.4356 19153 2573.9 27654 194 50 2583.8 2778.3 6.5870 197.42 2593.6 2791.0 200.30 2603.2 2803.5 6.5584 181.36 2570.9 2761.6 65289 175 180 185 184.44 2581O 2774.7 6.6148 6.6419 6.3380 187.26 2590.9 2787.5 6.5863 190.04 2600.7 2800.2 6.6137 6405 190 194
Steam undergoes an Isentropic process where it is initially at 1.05 MPa and 304C. The isentropic process causes its pressure to drop to 30 kPa. Find the tsat2, dryness, and enthalpy change. (69.10C, 90.4%, -657.34 kJ/kg) LO (179.91) 1.05 (182.04) (L Sat.) 10 v 10 194.44 2583.6 2778.1 6.5865 185.60 2585.I 2780.0 6.5696 Sat. 150 179.07 2532.0 2711 6.4342 182 29 2542.9 2725.1 6.4669 183.43 2553.4 2738.9 6.4984 188 50 25638 2752.3 6.3289 155 160 175.66 2550 0 2734.5 6.4678 165 178.64 2560.6 2748 2 6.4989 170 172.60 2539.2 2720.4 6.4356 19153 2573.9 27654 194 50 2583.8 2778.3 6.5870 197.42 2593.6 2791.0 200.30 2603.2 2803.5 6.5584 181.36 2570.9 2761.6 65289 175 180 185 184.44 2581O 2774.7 6.6148 6.6419 6.3380 187.26 2590.9 2787.5 6.5863 190.04 2600.7 2800.2 6.6137 6405 190 194
Refrigeration and Air Conditioning Technology (MindTap Course List)
8th Edition
ISBN:9781305578296
Author:John Tomczyk, Eugene Silberstein, Bill Whitman, Bill Johnson
Publisher:John Tomczyk, Eugene Silberstein, Bill Whitman, Bill Johnson
Chapter2: Matter And Energy
Section: Chapter Questions
Problem 29RQ: If 3000 ft3 of air is crossing an evaporator coil and iscooled from 75F to 55F, what would be the...
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