Std Deviation 2.18 2.3 pants Lit Room Vell Lit Room Mean 11.3 7.5 1194 556 Ho: u1 - u2 = 0 Ha: p1-p2 > 0 Null hypothesis: The shade of darkness does not have an impact of dishonesty Alt hypothesis: The shade of darkness does have an impact of dishonesty Level of Significance, a= 0.01 Sample #1 Mean of sample 1, xx1= 11.33 Standard deviation of sample 1, s1 = 2.18 Size of sample 1, n1= 9 Sample #2 Mean of sample 2, x2= 7.56 Standard deviation of sample 2, s2 = Size of sample 2, n2= 9 2.30 Difference in sample means = X1-X2 = 11.3300 - 7.6 = 3.77 Pooled std dev , Sp= v([[n1 - 1)s1² + (n2 - 1)s2*]/(n1+n2-2)) = 2.2408 Std error , SE = Sp*v(1/n1+1/n2) = 1.0563 T-statistic = ((x1-x2)-ud)/SE = ( 3.7700 - 0 )/ 1.06 = 3.569 Degree of freedom, DF= n1+n2-2 = 16 p-value = 0.001281 The p-value
Std Deviation 2.18 2.3 pants Lit Room Vell Lit Room Mean 11.3 7.5 1194 556 Ho: u1 - u2 = 0 Ha: p1-p2 > 0 Null hypothesis: The shade of darkness does not have an impact of dishonesty Alt hypothesis: The shade of darkness does have an impact of dishonesty Level of Significance, a= 0.01 Sample #1 Mean of sample 1, xx1= 11.33 Standard deviation of sample 1, s1 = 2.18 Size of sample 1, n1= 9 Sample #2 Mean of sample 2, x2= 7.56 Standard deviation of sample 2, s2 = Size of sample 2, n2= 9 2.30 Difference in sample means = X1-X2 = 11.3300 - 7.6 = 3.77 Pooled std dev , Sp= v([[n1 - 1)s1² + (n2 - 1)s2*]/(n1+n2-2)) = 2.2408 Std error , SE = Sp*v(1/n1+1/n2) = 1.0563 T-statistic = ((x1-x2)-ud)/SE = ( 3.7700 - 0 )/ 1.06 = 3.569 Degree of freedom, DF= n1+n2-2 = 16 p-value = 0.001281 The p-value
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
Related questions
Question
r2 = t2 /t2+df
= ( 3.569)^2 / ( 3.569)^2+16
=0.4432 = 44.32%
Present in a bar chart the difference in the

Transcribed Image Text:Std Deviation
2.18
2.3
pants
Lit Room
Vell Lit Room
Mean
11.3
7.5
1194
556
![Ho: u1 - u2 = 0
Ha: p1-p2 > 0
Null hypothesis: The shade of darkness does not have an impact of dishonesty
Alt hypothesis: The shade of darkness does have an impact of dishonesty
Level of Significance, a= 0.01
Sample #1
Mean of sample 1, xx1= 11.33
Standard deviation of sample 1, s1 =
2.18
Size of sample 1, n1= 9
Sample #2
Mean of sample 2, x2= 7.56
Standard deviation of sample 2, s2 =
Size of sample 2, n2= 9
2.30
Difference in sample means =
X1-X2 = 11.3300 - 7.6 = 3.77
Pooled std dev , Sp= v([[n1 - 1)s1² + (n2 - 1)s2*]/(n1+n2-2)) = 2.2408
Std error , SE = Sp*v(1/n1+1/n2) = 1.0563
T-statistic = ((x1-x2)-ud)/SE = ( 3.7700 - 0 )/ 1.06 = 3.569
Degree of freedom, DF= n1+n2-2 =
16
p-value =
0.001281
The p-value <a so you reject the null hypothesis, which is the shade of darkness does not have an
impact of dishonesty](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F3225cc6f-77cd-4314-acce-9e8b0be3f3f7%2F65d809cc-4428-44c0-a3b9-f7f563a36fef%2Fj7gbvgf.png&w=3840&q=75)
Transcribed Image Text:Ho: u1 - u2 = 0
Ha: p1-p2 > 0
Null hypothesis: The shade of darkness does not have an impact of dishonesty
Alt hypothesis: The shade of darkness does have an impact of dishonesty
Level of Significance, a= 0.01
Sample #1
Mean of sample 1, xx1= 11.33
Standard deviation of sample 1, s1 =
2.18
Size of sample 1, n1= 9
Sample #2
Mean of sample 2, x2= 7.56
Standard deviation of sample 2, s2 =
Size of sample 2, n2= 9
2.30
Difference in sample means =
X1-X2 = 11.3300 - 7.6 = 3.77
Pooled std dev , Sp= v([[n1 - 1)s1² + (n2 - 1)s2*]/(n1+n2-2)) = 2.2408
Std error , SE = Sp*v(1/n1+1/n2) = 1.0563
T-statistic = ((x1-x2)-ud)/SE = ( 3.7700 - 0 )/ 1.06 = 3.569
Degree of freedom, DF= n1+n2-2 =
16
p-value =
0.001281
The p-value <a so you reject the null hypothesis, which is the shade of darkness does not have an
impact of dishonesty
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