12:42 .ll 5GE O Today Edit 11:52 AM Q LIVE 6. A high school track and field coach wants to see if a new javelin model will help increase throw Tengths of his students. The table below lists the average length in meters using the old model and the new model for his 5 student athletes. Jerry 43.7 Tamar Rodney Alex Jin Old Javelin 41.1 47 41.8 41.9 New Javelin 44.5 42.9 47.3 42.5 43.5 Difference d P. -0.8 -1.8 -0.3 -0.7 -1.6 -1.04 XXXXXXXX XXXXXXXX (а - d) 0.24 -0.76 0.74 0.34 -0.56 0.0576 0.5776 0.5476 0.1156 0.3136 ¿(P - P) The manufacturer of the new javelin claims that the new javelin model will improve lengths of throws. Hi represents the population mean throw length of the old javelin model. Hz represents the population mean throw length of the new javelin model. Ho:H1 = H2 Hai Hi < Hz (Claim) At the 0.01 level of significance, is there enough evidence to reject Ho and support the manufacturer's claim? A. Yes, the test statistic t = -3.66 is in the rejection region with critical value -3.7469 B. No, the test statistic t = –3.66 is not in the rejection region with critical value -3.7469 C. Yes, the test statistic t = –3.71 is in the rejection region with critical value -3.66 D. No, the test statistic t = -3.75 is not in the rejection region with critical value -3.66 E. Yes, the test statistic t = –3.75 is in the rejection region with critical value -3.7469
12:42 .ll 5GE O Today Edit 11:52 AM Q LIVE 6. A high school track and field coach wants to see if a new javelin model will help increase throw Tengths of his students. The table below lists the average length in meters using the old model and the new model for his 5 student athletes. Jerry 43.7 Tamar Rodney Alex Jin Old Javelin 41.1 47 41.8 41.9 New Javelin 44.5 42.9 47.3 42.5 43.5 Difference d P. -0.8 -1.8 -0.3 -0.7 -1.6 -1.04 XXXXXXXX XXXXXXXX (а - d) 0.24 -0.76 0.74 0.34 -0.56 0.0576 0.5776 0.5476 0.1156 0.3136 ¿(P - P) The manufacturer of the new javelin claims that the new javelin model will improve lengths of throws. Hi represents the population mean throw length of the old javelin model. Hz represents the population mean throw length of the new javelin model. Ho:H1 = H2 Hai Hi < Hz (Claim) At the 0.01 level of significance, is there enough evidence to reject Ho and support the manufacturer's claim? A. Yes, the test statistic t = -3.66 is in the rejection region with critical value -3.7469 B. No, the test statistic t = –3.66 is not in the rejection region with critical value -3.7469 C. Yes, the test statistic t = –3.71 is in the rejection region with critical value -3.66 D. No, the test statistic t = -3.75 is not in the rejection region with critical value -3.66 E. Yes, the test statistic t = –3.75 is in the rejection region with critical value -3.7469
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
Related questions
Question
![12:42
.ll 5GE O
Today
Edit
11:52 AM
Q LIVE
6. A high school track and field coach wants to see if a new javelin model will help increase throw
Tengths of his students. The table below lists the average length in meters using the old model
and the new model for his 5 student athletes.
Jerry
43.7
Tamar
Rodney
Alex
Jin
Old Javelin
41.1
47
41.8
41.9
New Javelin
44.5
42.9
47.3
42.5
43.5
Difference d
P.
-0.8
-1.8
-0.3
-0.7
-1.6
-1.04
XXXXXXXX
XXXXXXXX
(а - d)
0.24
-0.76
0.74
0.34
-0.56
0.0576
0.5776
0.5476
0.1156
0.3136
¿(P - P)
The manufacturer of the new javelin claims that the new javelin model will improve lengths of
throws.
Hi represents the population mean throw length of the old javelin model.
Hz represents the population mean throw length of the new javelin model.
Ho:H1 = H2
Hai Hi < Hz (Claim)
At the 0.01 level of significance, is there enough evidence to reject Ho and support the
manufacturer's claim?
A. Yes, the test statistic t = -3.66 is in the rejection region with critical value -3.7469
B. No, the test statistic t = –3.66 is not in the rejection region with critical value -3.7469
C. Yes, the test statistic t = –3.71 is in the rejection region with critical value -3.66
D. No, the test statistic t = -3.75 is not in the rejection region with critical value -3.66
E. Yes, the test statistic t = –3.75 is in the rejection region with critical value -3.7469](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fa39be845-ae1d-44f6-957a-0c42c0fe4c23%2Ff128cb72-1d79-47ea-8b84-fa4226bec28d%2F9ku9npd_processed.png&w=3840&q=75)
Transcribed Image Text:12:42
.ll 5GE O
Today
Edit
11:52 AM
Q LIVE
6. A high school track and field coach wants to see if a new javelin model will help increase throw
Tengths of his students. The table below lists the average length in meters using the old model
and the new model for his 5 student athletes.
Jerry
43.7
Tamar
Rodney
Alex
Jin
Old Javelin
41.1
47
41.8
41.9
New Javelin
44.5
42.9
47.3
42.5
43.5
Difference d
P.
-0.8
-1.8
-0.3
-0.7
-1.6
-1.04
XXXXXXXX
XXXXXXXX
(а - d)
0.24
-0.76
0.74
0.34
-0.56
0.0576
0.5776
0.5476
0.1156
0.3136
¿(P - P)
The manufacturer of the new javelin claims that the new javelin model will improve lengths of
throws.
Hi represents the population mean throw length of the old javelin model.
Hz represents the population mean throw length of the new javelin model.
Ho:H1 = H2
Hai Hi < Hz (Claim)
At the 0.01 level of significance, is there enough evidence to reject Ho and support the
manufacturer's claim?
A. Yes, the test statistic t = -3.66 is in the rejection region with critical value -3.7469
B. No, the test statistic t = –3.66 is not in the rejection region with critical value -3.7469
C. Yes, the test statistic t = –3.71 is in the rejection region with critical value -3.66
D. No, the test statistic t = -3.75 is not in the rejection region with critical value -3.66
E. Yes, the test statistic t = –3.75 is in the rejection region with critical value -3.7469
Expert Solution
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Step 1
Two samples are called paired samples if the sample data is collected using same elements but under two different conditions. The paired sample t test is used to compare the mean of such data.
This test uses the difference in paired data as single sample. The test statistic is computed by , where is the mean difference, is population mean difference claimed in null hypothesis, is sample standard deviation of difference and n is sample size.
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