webassigh.he E scr In large crporation, an "intimidator" is an employee who tries to stop communication, wometimes sabotages others, and, above al, likes to listen to him or herself talk. Let be a random variable representing productive hours perwok lost by peer emplovees of an intimidater : 736 2 25 2 A'stress" is an employee with a hot temper that Inads to unproductive tantrums in corporate sooety. Let y be a random variable representing productive hours per week lost by peer employees of a stressor. y 33 10 s6258 A USE SALT Use a calculator with sample mean and sample standard devietion keys to calouiste , Fu, and s (Round vour answers to four decimal places.) S-73417 - 5625 - 20754 (a) Aasuming the variables and y are independent, do the data indicate that the population mean time lost due to stressors is greater then the population meen time lost due to intimidators? Use a 5 level of signficance. (Aasume the population distributions of time lost due to intimidators and time lost due to stressors are each mound-shaped and symmetric.) what is the level of signficance State the nul and altemate hypotheses O Hot -gi M Ma O Hot 0.250 O 0.125 < P-value <0.250 O0.050 < P-value <0.125 O 0.025 e Pvalue 0.050 O 0.005 Pvalue e 0.025 OPvalue < D.005 Sketch the sampling detriution and show the area corresponding to the Pvalue. . () Based on your answers in parts ()-(), will you reject or fail to reject the null hypothesis? Are the data statistically significant at level a? O At the eD,05 level, we reject the nul hypothesis and condude the data ere statistically significant. OM the a-0.05 level, we fail to reject the null hypothesis and conclude the data are stabstically significent. O At the a-0.05 level, we reject the null hypothesis and conclude the date are not statisticelly significant O At the -0.05 leve, we fal to reject the nul hypathesis and condude the data are not statisticaly significant. (v) Interpret your conclusion in the context of the application O Reject the nul hypothesa, there is insufficent evidence that the mean tme lost due to stressors is greater than the mean time lost due to intimidators- O Reject the nul hypothesis, there is sufficient evidence that the meen time iost due to stressors is greater than the mean time lost due to intimidators. O Fail to reject the null hypothesis, there s insufficient evidence that the mean time lost due to stressors is greater than the mean time lost due to intimidators O Fail to reject the null hypothesis, there is sufficent evidance that the mean time lost due to stressors is greater than the meen time lost due to intimidators. (b) Finda 90 ortidence interval for - (Round yaur answers to twe decimal piaces.) Ipwer lt upper lime Explain the meaning of the confidence interval in the contet of the prabiem O Recause the interval contans only positive numbers, this ndicates that at the SO confidence level, the popaton mean tme lost due to stressors" is ess than the population mean time lost due to "ietimidators. O Because the interval contana both postive and negate rumbers. this ind atas that at the s0 confidence evel, we cannot say that there is any difference in time lost due to "ietimidators" and "stressors O Because the interval contsns both postve end negatenumbers, this indicates that at the 90s confderice d.there saoference in time lost due to ntimidators and "stressors. Because the interval oor tant only hegstive numbers, tha indicatas that at the B0%confidence evel the prpulation mean time cst due to "stressors" s greater than the population meen time iost due to "ntimidators

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webassigh.he
E scr
In large crporation, an "intimidator" is an employee who tries to stop communication, wometimes sabotages others, and, above al, likes to listen to him or herself talk. Let be a random variable representing productive hours
perwok lost by peer emplovees of an intimidater
: 736 2 25 2
A'stress" is an employee with a hot temper that Inads to unproductive tantrums in corporate sooety. Let y be a random variable representing productive hours per week lost by peer employees of a stressor.
y 33 10 s6258
A USE SALT
Use a calculator with sample mean and sample standard devietion keys to calouiste , Fu, and s (Round vour answers to four decimal places.)
S-73417
- 5625
-
20754
(a) Aasuming the variables and y are independent, do the data indicate that the population mean time lost due to stressors is greater then the population meen time lost due to intimidators? Use a 5 level of
signficance. (Aasume the population distributions of time lost due to intimidators and time lost due to stressors are each mound-shaped and symmetric.)
what is the level of signficance
State the nul and altemate hypotheses
O Hot -gi M Ma
O Hot <H H
O Ho: - Hy
(e) What samping distribution will you use? ihat assumpticns are you makng?
O The standard normal. We assume thet both population distributions are ooroimately narmal wth known standard devations
O The Student'st We assume that both population distributions re acorimately normel with known atanderd devistions
O The standard normal. We assume that both popuieton dstributors are appromatay nomal with unlenown standard deviations
O The Studentst We essume that both population distrbutions are approimatel normis wth unknown standard deviations.
What is the vaiut of the sampe test statiatic Compute the comesoonding ortalue s acorcorate (Test the dfference Do not use rounded velues Round your finel answer to three deoma places
(w) Find (or estimate) the Pvalun.
OPvalue > 0.250
O 0.125 < P-value <0.250
O0.050 < P-value <0.125
O 0.025 e Pvalue 0.050
O 0.005 Pvalue e 0.025
OPvalue < D.005
Sketch the sampling detriution and show the area corresponding to the Pvalue.
.
() Based on your answers in parts ()-(), will you reject or fail to reject the null hypothesis? Are the data statistically significant at level a?
O At the eD,05 level, we reject the nul hypothesis and condude the data ere statistically significant.
OM the a-0.05 level, we fail to reject the null hypothesis and conclude the data are stabstically significent.
O At the a-0.05 level, we reject the null hypothesis and conclude the date are not statisticelly significant
O At the -0.05 leve, we fal to reject the nul hypathesis and condude the data are not statisticaly significant.
(v) Interpret your conclusion in the context of the application
O Reject the nul hypothesa, there is insufficent evidence that the mean tme lost due to stressors is greater than the mean time lost due to intimidators-
O Reject the nul hypothesis, there is sufficient evidence that the meen time iost due to stressors is greater than the mean time lost due to intimidators.
O Fail to reject the null hypothesis, there s insufficient evidence that the mean time lost due to stressors is greater than the mean time lost due to intimidators
O Fail to reject the null hypothesis, there is sufficent evidance that the mean time lost due to stressors is greater than the meen time lost due to intimidators.
(b) Finda 90 ortidence interval for - (Round yaur answers to twe decimal piaces.)
Ipwer lt
upper lime
Explain the meaning of the confidence interval in the contet of the prabiem
O Recause the interval contans only positive numbers, this ndicates that at the SO confidence level, the popaton mean tme lost due to stressors" is ess than the population mean time lost due to "ietimidators.
O Because the interval contana both postive and negate rumbers. this ind atas that at the s0 confidence evel, we cannot say that there is any difference in time lost due to "ietimidators" and "stressors
O Because the interval contsns both postve end negatenumbers, this indicates that at the 90s confderice d.there saoference in time lost due to ntimidators and "stressors.
Because the interval oor tant only hegstive numbers, tha indicatas that at the B0%confidence evel the prpulation mean time cst due to "stressors" s greater than the population meen time iost due to
"ntimidators
Transcribed Image Text:webassigh.he E scr In large crporation, an "intimidator" is an employee who tries to stop communication, wometimes sabotages others, and, above al, likes to listen to him or herself talk. Let be a random variable representing productive hours perwok lost by peer emplovees of an intimidater : 736 2 25 2 A'stress" is an employee with a hot temper that Inads to unproductive tantrums in corporate sooety. Let y be a random variable representing productive hours per week lost by peer employees of a stressor. y 33 10 s6258 A USE SALT Use a calculator with sample mean and sample standard devietion keys to calouiste , Fu, and s (Round vour answers to four decimal places.) S-73417 - 5625 - 20754 (a) Aasuming the variables and y are independent, do the data indicate that the population mean time lost due to stressors is greater then the population meen time lost due to intimidators? Use a 5 level of signficance. (Aasume the population distributions of time lost due to intimidators and time lost due to stressors are each mound-shaped and symmetric.) what is the level of signficance State the nul and altemate hypotheses O Hot -gi M Ma O Hot <H H O Ho: - Hy (e) What samping distribution will you use? ihat assumpticns are you makng? O The standard normal. We assume thet both population distributions are ooroimately narmal wth known standard devations O The Student'st We assume that both population distributions re acorimately normel with known atanderd devistions O The standard normal. We assume that both popuieton dstributors are appromatay nomal with unlenown standard deviations O The Studentst We essume that both population distrbutions are approimatel normis wth unknown standard deviations. What is the vaiut of the sampe test statiatic Compute the comesoonding ortalue s acorcorate (Test the dfference Do not use rounded velues Round your finel answer to three deoma places (w) Find (or estimate) the Pvalun. OPvalue > 0.250 O 0.125 < P-value <0.250 O0.050 < P-value <0.125 O 0.025 e Pvalue 0.050 O 0.005 Pvalue e 0.025 OPvalue < D.005 Sketch the sampling detriution and show the area corresponding to the Pvalue. . () Based on your answers in parts ()-(), will you reject or fail to reject the null hypothesis? Are the data statistically significant at level a? O At the eD,05 level, we reject the nul hypothesis and condude the data ere statistically significant. OM the a-0.05 level, we fail to reject the null hypothesis and conclude the data are stabstically significent. O At the a-0.05 level, we reject the null hypothesis and conclude the date are not statisticelly significant O At the -0.05 leve, we fal to reject the nul hypathesis and condude the data are not statisticaly significant. (v) Interpret your conclusion in the context of the application O Reject the nul hypothesa, there is insufficent evidence that the mean tme lost due to stressors is greater than the mean time lost due to intimidators- O Reject the nul hypothesis, there is sufficient evidence that the meen time iost due to stressors is greater than the mean time lost due to intimidators. O Fail to reject the null hypothesis, there s insufficient evidence that the mean time lost due to stressors is greater than the mean time lost due to intimidators O Fail to reject the null hypothesis, there is sufficent evidance that the mean time lost due to stressors is greater than the meen time lost due to intimidators. (b) Finda 90 ortidence interval for - (Round yaur answers to twe decimal piaces.) Ipwer lt upper lime Explain the meaning of the confidence interval in the contet of the prabiem O Recause the interval contans only positive numbers, this ndicates that at the SO confidence level, the popaton mean tme lost due to stressors" is ess than the population mean time lost due to "ietimidators. O Because the interval contana both postive and negate rumbers. this ind atas that at the s0 confidence evel, we cannot say that there is any difference in time lost due to "ietimidators" and "stressors O Because the interval contsns both postve end negatenumbers, this indicates that at the 90s confderice d.there saoference in time lost due to ntimidators and "stressors. Because the interval oor tant only hegstive numbers, tha indicatas that at the B0%confidence evel the prpulation mean time cst due to "stressors" s greater than the population meen time iost due to "ntimidators
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