-Question Completion Status:O d. ANOVAQUESTION 8The calculated value for your Chi Square crosstabulation comes in at 9.34. The test has 4 degrees of freedom. Given a .05alpha level, would you reject the null hypothesis?O a. yes, because 4 degrees of freedom allows me to judge that the calculated value is close enough to the critical valueO b. yes, because the calculated value is larger than the critical value for .05 alpha with 4 degrees of freedom.O C. no, because the calculated value does not exceed the critical value for .05 alpha at 4 degrees of freedomO d. no, because a Chi-Square test with 4 degrees of freedom is too "loose" to be validQUESTION 9Click Save and Submit to save and submit. Click Save All Answers to save all answers.NAYAa11AlebrateMacBook Airspa

We have given that Calculated Chi-Square value = 9.34 Degrees of freedom = 4 Significance level =…

Answered: -Question Completion Status: O d. ANOVA…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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This Question: 4 pts 1 of 9 (0 complete) This Quiz: 45 pts possible Assume a significance level of a = 0.05 and use the given information to complete parts (a) and (b) below. Original claim: More than 54% of adults would erase all of their personal information online if they could. The hypothesis test results in a P-value of 0.1661. a. State a conclusion about the null hypothesis. (Reject H, or fail to reject Ho.) Choose the correct answer below. A. Reject Ho because the P-value is greater than a. B. Reject Ho because the P-value is less than or equal to a. C. Fail to reject H, because the P-value is less than or equal to a. O D. Fail to reject H, because the P-value is greater than a. b. Without using technical terms, state a final conclusion that addresses the original claim. Which of the following is the correct conclusion? A. There is sufficient evidence to support the claim that the percentage of adults that would erase all of their personal information online if they could is…
a. Compute the p-value for the test (use R). Round to the nearest 3rd decimal place, 0.xxx. b. Make and justify a statistical decision at the α= 0.15 significance level and state your conclu-sions in context of the problem.
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Please answer within 30min thanks.Answer Letter D Eonly choices provided in pic.
Ex K A 2 Consider a sample of 49 football games, where 30 of them were won by the home team. Use a 0.10 significance level to test the claim that the probability that the home team wins is greater than one-half. W S Identify the null and alternative hypotheses for this test. Choose the correct answer below. A. Ho: p=0.5 H₁: p>0.5 OB. Ho: p=0.5 H₁: p0.5 H₁: p=0.5 D Identify the test statistic for this hypothesis test. The test statistic for this hypothesis test is (Round to two decimal places as needed.) X mmand дв Monroe's Temp....docx. Removed 3 8.0 E D C $ 4 FA R F W SAMPLE Persuas....pdf % 5 V V T G 6 A B MacBook Air & Y 5373255 (1) (1).docx H & 7 U N * 8 J A DII 1 M ( 9 5373255 (1).docx K O < 1 H O L F 10 Clear all P Л. ... I PR { + Check answer ? command option Show All 1 F12 X L 1 de
A random sample of size 25 from a normal population has a mean of x-bar = 62.8 and s = 3.55. If you were to test the following hypothesis at the .05 level of significance. The value of the test statistic is Họ: H = 60 %3D Họ: H+60 O-3.94 O 0.79 -0.79 O 3.94 O 2.8
State the Result: A hypothesis test was conducted at the alpha = 0.01 level of significance. The test resulted in a p-value of 0.044.
Under what circumstances is a t statistic used instead of a z-score for a hypothesis test? Justin wants to know whether a commonly prescribed drug does improve the attention span of students with attention deficit disorder (ADD). He knows that the mean attention span for students with ADD who are not taking the drug is 2.3 minutes long. His sample of 12 students taking the drug yielded a mean of 4.6 minutes. Justin can find no information regarding σx , so he calculated s2x =1.96. Determine the critical region using a one-tailed test with alpha = .05. Conduct the hypothesis test (Do the math and compare the t-critical and t-obtained values). State your conclusions in terms of H0 (Should you reject the H0 or fail to reject/accept the H0). Based on your analysis, is there a relationship between the drug and attention span?
What is the critical t score if you are testing a one-tailed hypothesis, α level of .05 with df = 36? a. 1.671 b. 2.026 c. 2.028 d. 1.697
Identify the type I error and the type Il error that corresponds to the given hypothesis. The proportion of people who write with their left hand is equal to 0.17. Which of the following is a type I error? O A. Reject the claim that the proportion of people who write with their left hand is 0.17 when the proportion is actually 0.17. O B. Fail to reject the claim that the proportion of people who write with their left hand is 0.17 when the proportion is actually 0.17. O C. Reject the claim that the proportion of people who write with their left hand is 0.17 when the proportion is actually different from 0.17. O D. Fail to reject the claim that the proportion of people who write with their left hand is 0.17 when the proportion is actually different from 0.17. Which of the following is a type Il error? O A. Fail to reject the claim that the proportion of people who write with their left hand is 0.17 when the proportion is actually different from 0.17. OB. Reject the claim that the…
Is the following statements correct or incorrect: Suppose that a random vector Y' = (Y1, Y2, Y3) has multi-normal distribution with mean vector u and variance-covariance matrix £ given by and Σ 흑 0 1 respectively. CH), Then the distribution of Z = Y is N 1
In a one-tail hypothesis test where you reject H0 only in the lower tail, it was found that the p-value is 0.1469 if ZSTAT=−1.05. What is your statistical decision if you test the null hypothesis at the 0.05 level of significance? Question content area bottom Part 1 Choose the correct answer below. A. Reject the null hypothesis because the p-value is less than the level of significance. B. Reject the null hypothesis because the p-value is greater than the level of significance. C. Fail to reject the null hypothesis because the p-value is greater than the level of significance. D. Fail to reject the null hypothesis because the p-value is less than the level of significance.

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