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!! IM- || Done Topic 2 (2 of 4) loannis Kyriakou Introduction to Probability and Statistics Numerical Data Summaries 20/28 Example Calculate the sample mean and standard deviation of the following values: 534 671 581 620 401 340 980 845 550 690 • n= 10 =Σx-621.20 (SH675TH204 fotH:360+98043451550190)=621.2 = 621.202 = 385, 889.44 E x} = 4, 186, 784 i=1 = S O n-1 x? – nx2 = 190.87 - f 5.00. 21/28 Numerical Data Summaries loannis Kyriakou Introduction to Probability and Statistics Example ext page %D

!! IM- || Done Topic 2 (2 of 4) loannis Kyriakou Introduction to Probability and Statistics Numerical Data Summaries 20/28 Example Calculate the sample mean and standard deviation of the following values: 534 671 581 620 401 340 980 845 550 690 • n= 10 =Σx-621.20 (SH675TH204 fotH:360+98043451550190)=621.2 = 621.202 = 385, 889.44 E x} = 4, 186, 784 i=1 = S O n-1 x? – nx2 = 190.87 - f 5.00. 21/28 Numerical Data Summaries loannis Kyriakou Introduction to Probability and Statistics Example ext page %D

MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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I was reading through my lecture notes and I'm not sure how they got 4,186,784. 

!! IM- || Done Topic 2 (2 of 4) loannis Kyriakou Introduction to Probability and Statistics Numerical Data Summaries 20/28 Example Calculate the sample mean and standard deviation of the following values: 534 671 581 620 401 340 980 845 550 690 • n= 10 =Σx-621.20 (SH675TH204 fotH:360+98043451550190)=621.2 = 621.202 = 385, 889.44 E x} = 4, 186, 784 i=1 = S O n-1 x? – nx2 = 190.87 - f 5.00. 21/28 Numerical Data Summaries loannis Kyriakou Introduction to Probability and Statistics Example ext page %D
Transcribed Image Text:!! IM- || Done Topic 2 (2 of 4) loannis Kyriakou Introduction to Probability and Statistics Numerical Data Summaries 20/28 Example Calculate the sample mean and standard deviation of the following values: 534 671 581 620 401 340 980 845 550 690 • n= 10 =Σx-621.20 (SH675TH204 fotH:360+98043451550190)=621.2 = 621.202 = 385, 889.44 E x} = 4, 186, 784 i=1 = S O n-1 x? – nx2 = 190.87 - f 5.00. 21/28 Numerical Data Summaries loannis Kyriakou Introduction to Probability and Statistics Example ext page %D
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