# Estimating a Population Mean from Sample Data The goal is to estimate a population mean (\(\mu\)) from the following sample data: | 71.4 | 56.5 | 57.2 | 57.5 | |------|------|------|------| | 48.0 | 53.6 | 61.7 | 51.3 | | 65.5 | 51.3 | 54.8 | 69.8 | | 52.7 | 61.6 | 77.3 | 53.6 | | 47.8 | 59.6 | 56.4 | 65.4 | | 51.2 | 69.9 | 48.4 | 73.5 | | 64.9 | 63.9 | 62.1 | 60.8 | | 48.4 | 55.5 | 50.8 | 63.5 | | 70.5 | 71.1 | 71.6 | 56.3 | | 62.5 | 57.8 | 64.4 | 51.1 | | 59.4 | 58.8 | 49.8 | 49.8 | | 54.3 | 54.2 | 57.8 | 67.8 | | 59.9 | 63.5 | 63.4 | 65.9 | | 71.1 | ## Confidence Interval Calculation **Task:** Find the 99% confidence interval for the population mean \(\mu\). - **Instructions:** Enter your answer as a tri-linear inequality accurate to two decimal places (since the sample data are reported to one decimal place). \[ < \mu < \] - **Note:** The answer should be obtained without any preliminary rounding. However, the critical value may be rounded to three decimal places. **Question Help:** [Message instructor] **Submission:** Click on "Submit Question" to record your response.

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# Estimating a Population Mean from Sample Data

The goal is to estimate a population mean (\(\mu\)) from the following sample data:

| 71.4 | 56.5 | 57.2 | 57.5 |
|------|------|------|------|
| 48.0 | 53.6 | 61.7 | 51.3 |
| 65.5 | 51.3 | 54.8 | 69.8 |
| 52.7 | 61.6 | 77.3 | 53.6 |
| 47.8 | 59.6 | 56.4 | 65.4 |
| 51.2 | 69.9 | 48.4 | 73.5 |
| 64.9 | 63.9 | 62.1 | 60.8 |
| 48.4 | 55.5 | 50.8 | 63.5 |
| 70.5 | 71.1 | 71.6 | 56.3 |
| 62.5 | 57.8 | 64.4 | 51.1 |
| 59.4 | 58.8 | 49.8 | 49.8 |
| 54.3 | 54.2 | 57.8 | 67.8 |
| 59.9 | 63.5 | 63.4 | 65.9 |
| 71.1 |

## Confidence Interval Calculation

**Task:** Find the 99% confidence interval for the population mean \(\mu\).

- **Instructions:** Enter your answer as a tri-linear inequality accurate to two decimal places (since the sample data are reported to one decimal place).

\[
< \mu <
\]

- **Note:** The answer should be obtained without any preliminary rounding. However, the critical value may be rounded to three decimal places.

**Question Help:** [Message instructor]

**Submission:** Click on "Submit Question" to record your response.
Transcribed Image Text:# Estimating a Population Mean from Sample Data The goal is to estimate a population mean (\(\mu\)) from the following sample data: | 71.4 | 56.5 | 57.2 | 57.5 | |------|------|------|------| | 48.0 | 53.6 | 61.7 | 51.3 | | 65.5 | 51.3 | 54.8 | 69.8 | | 52.7 | 61.6 | 77.3 | 53.6 | | 47.8 | 59.6 | 56.4 | 65.4 | | 51.2 | 69.9 | 48.4 | 73.5 | | 64.9 | 63.9 | 62.1 | 60.8 | | 48.4 | 55.5 | 50.8 | 63.5 | | 70.5 | 71.1 | 71.6 | 56.3 | | 62.5 | 57.8 | 64.4 | 51.1 | | 59.4 | 58.8 | 49.8 | 49.8 | | 54.3 | 54.2 | 57.8 | 67.8 | | 59.9 | 63.5 | 63.4 | 65.9 | | 71.1 | ## Confidence Interval Calculation **Task:** Find the 99% confidence interval for the population mean \(\mu\). - **Instructions:** Enter your answer as a tri-linear inequality accurate to two decimal places (since the sample data are reported to one decimal place). \[ < \mu < \] - **Note:** The answer should be obtained without any preliminary rounding. However, the critical value may be rounded to three decimal places. **Question Help:** [Message instructor] **Submission:** Click on "Submit Question" to record your response.
Expert Solution
Step 1

The data set is:

71.4
48
65.5
52.7
47.8
51.2
64.9
48.4
40.4
62.5
72.3
54.3
59.9
71.1
56.5
53.6
51.4
61.6
59.6
69.9
63
55.5
71.2
57.8
58.8
54.2
63.5
57.2
61.7
56.8
77.3
56.4
48.4
62.1
50.8
71.6
64.4
69
57.8
63.4
57.5
51.3
69.8
53.6
65.4
73.5
60.8
63.5
56.3
51.1
49.8
67.8
65.9
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