TributaryIçáJutaíJapuráCoariPurusManacapuruNegroMadeiraTrombetasTapajósXinguTocantinsUpstreamnumberof species10. Circulatory Phy....pdf4°CMostly cloudy141185105232919162510Downstreamnumber ofspeciesa. What is the mean difference in the number ofspecies between areas upstream and down-stream of a tributary? What is the 95% confi-dence interval of this mean difference?b. Test the hypothesis that the tributarieshave no effect on the number of species ofelectric fish.19188716624301620211211. Circulatory Phy....pdfA

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Answered: Tributary Içá Jutaí Japurá Coari Purus…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Find the 4 yearly moving averages from the following data (1) by centering the averages and (i) by centering the totals : Year: 1989 | 1990 1991 | 1992 | 1993 | 1994 | 1995 | 1996 | 1997 | 1998 Prodn. (in tonnes) : 75 85 98 90 95 108 124 140 150 160
Bayyinah TV Meet - dzg-qtng-hpj PDF Reader - View,.. Approximate the measures of center for following GFDT. Data Frequency 50 -54 55-59 60 - 64 65 - 69 70-74 75 - 79 7. 80 - 84 15 85 - 89 90 -94 18 15 mode = median = mean = Report mode and median accurate to one decimal place. Report the mean accurate places (or enter as a fraction). Question Help: DPstto forum 9 Type here to search dn
Make an interpretation for the given picture below. Please refer to the subsequent picture for your guide in constructing your interpretation in the given table.
Approximate the measures of center for following GFDT. Data Frequency 30 - 34 2 35 - 39 0 40 - 44 14 45 - 49 20 50 - 54 13 Report mode and median accurate to one decimal place. Report the mean accurate to two decimal places (or enter as a fraction). (a) mode = (b) median = (c) mean =
Data was collected for 300 fish from the North Atlantic. The length of the fish (in mm) is summarized in the frequency distribution below. Lengths (mm) Frequency 180 - 184 1 185 - 189 16 190 - 194 71 195 - 199 108 200 - 204 83 205 - 209 18 210 - 214 3 What is the lower class boundary for the first class?class boundary =
The data in the table characterizes the income distribution for a country. Income category Share of income (%) Cumulative share of income (%) first quintile 7.0 --- second quintile 9.0 16.0 third quintile --- 37.0 fourth quintile 25.0 --- fifth quintile 38.038.0 --- What percentage of the total population is categorized as belonging to the second quintile? Give your responses as whole numbers. Percentage of population in second quintile:__________% What percentage of the total income for the country is earned by the third quintile? Percentage earned by the third quintile:__________% What is the cumulative share of income earned by the poorest 80% of the population? Percentage earned by the poorest 80%:__________%
The data given below represent the percentage of energy derived from coal from the 50 states plus the District of Columbia. Construct both grouped frequency and grouped relative frequency distribution with class width 10.0 and starting lower class limit 0.0. 0, 0, 0, 0.9, 1.3, 2.7, 8.0, 8.4, 8.5, 10.3, 13.3, 15.6, 16.6, 23.2, 23.3, 27.4, 32.4, 34.6, 36.8, 38.3, 40.6, 42.4, 46.1, 48.5, 50.8, 51.1, 54.2, 55.7, 56.6, 57.7, 59.5, 60.2, 60.4, 60.8, 62.1, 62.3, 63.1, 64.3, 68.1, 75.0, 77.6, 83.1, 83.2, 87.7, 90.4, 90.4, 93.7, 94.2, 94.6, 95.8, 98.1
Use the given data for creation of a table with lowest limit as the lowest value and class interval of 5. Use that table for calculation of cumulative frequency, reverse cumulative frequency, relative frequency. Use Excel for these calculations. Then calculate the mean, median and mode of the data through that frequency table by manual calculation. 58 54 85 88 89 88 82 81 77 63 86 52 48 42 69 46 41 84 40 57 57 54 60 43 62 50 73 89 56 48 52 51 83 46 81 60 85 89 51 60 58 63 42 64 76 89 80 70 41 80 74 57 79 82 77 63 69 55 90 79 67 87 48 57 81 58 68 66 61 55 48 68 56 57 89 77 86 87 49 75 73 64 50 49 80 74 80 65 79 82 46 57 81 60 80 48
Data was collected for 300 fish from the North Atlantic. The length of the fish (in mm) is summarized in the GFDT below. Lengths (mm) Frequency 160 - 174 1 175 - 189 16 190 - 204 71 205 - 219 108 220 - 234 83 235 - 249 18 250 - 264 3 What is the class midpoint for the second class?class midpoint =
Directions: Find the best point estimate for the population mean and its standard error for each set of samples. GIVEN SOLUTION 1. Weights in kilograms of 7 Grade 11students 45, 58, 42, 54, 66, 54, 43 population variance - 100 2. Daily allowance of 10 Grade 12 students 100, 70, 120, 150, 80, 75, 100, 50, 85, 100 population variance - 100 A manufacturer produces paper that has a mean length of 10 inches and a standard deviation of 0.1. Twenty-five papers are sampled and measured with a mean paper length of 9.50 in. QUESTION SOLUTION a. What is the best point estimate for the true mean length of the paper? b. What is the standard crror of this point estimate? c. What is the maximum error of this point estimate? d. Construct interval for the true mean length of a 95% confidence paper produced by this company.
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400 350 0383 300 250 -271.8 200 150 173.7 X1369106383 100 133.1 85 50 -45.2 Annual rainfalls for Metropolis are given in the following table ("Annual maximums of," 2013). The box plot above provides one visual depiction of the data distribution. Use it or construct a frequency table and/or frequency histogram (use 8 classes) to analyze the distribution of this data. Then, select which of the following statements about distribution of this data is most correct: Table: Annual Rainfall in Metropolis 146.8 383 90.9 178.1 267.5 95.5 156.5 180 90.9 139.7 200.2 171.7 187.2 184.9 70.1 58 84.1 55.6 133.1 271.8 135.9 71.9 99.4 110.6 47.5 97.8 122.7 58.4 154.4 173.7 118.8 88 84.6 171.5 254.3 185.9 137.2 138.9 96.2 85 45.2 74.7 264.9 113.8 133.4 68.1 156.4 Question 5 options: A) Data appears NOT to be distributed normally (unimodal but mean appears to be less than median); one outlier exists (383); skew to left is discernable and supports relationship of mean to median B) Data appears to be…

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