STATISTICAL ANALYSIS (No long explanation needed. Rate will be given and write the complete solutions.) CI on Mean, Variance Unknown, Prediction and Tolerance Interval A CNC (computer numerical control) machine produces iron automobile crankshafts. Samples are measured and the inner diameter are found to be 1.01, 0.97, 1.03, 1.04, 0.99, 0.98, 0.99, 1.01, and 1.03 centimeters. For all computations, assume an approximately normal distribution. The sample mean and standard deviation for the given data are = 1.0056, and s = 0.0246. Find a 99% confidence interval on the mean of diameter. Compute a 99% prediction interval on a measured diameter of a single crankshaft piece taken from the machine. Find the 99% tolerance limits that will contain most of the metal pieces produced by the CNC machine. Choose the correct answer. a. CI on the mean: 0.970 < μ < 1.9845. Prediction Interval: 0.9186 ≤ Xn+1 ≤ 1.0926. Tolerance Interval (0.8937 and 1.1175) b. CI on the mean: 0.9781 < μ < 1.0331. Prediction Interval: 0.9186 ≤ Xn+1 ≤ 1.0926. Tolerance Interval (0.8937 and 1.1175). Insufficient data to compute for the Tolerance Interval c. Insufficient data to compute. Missing the sample size n d. CI on the mean: 0.9781 < μ < 1.0331. Prediction Interval: 0.9186 ≤ Xn+1 ≤ 1.0926. Tolerance Interval (0.8937 and 1.1175)
STATISTICAL ANALYSIS (No long explanation needed. Rate will be given and write the complete solutions.)
CI on
A CNC (computer numerical control) machine produces iron automobile crankshafts. Samples are measured and the inner diameter are found to be 1.01, 0.97, 1.03, 1.04, 0.99, 0.98, 0.99, 1.01, and 1.03 centimeters. For all computations, assume an approximately
Find a 99% confidence interval on the mean of diameter. Compute a 99% prediction interval on a measured diameter of a single crankshaft piece taken from the machine. Find the 99% tolerance limits that will contain most of the metal pieces produced by the CNC machine.
Choose the correct answer.
a. CI on the mean: 0.970 < μ < 1.9845. Prediction Interval: 0.9186 ≤ Xn+1 ≤ 1.0926. Tolerance Interval (0.8937 and 1.1175)
b. CI on the mean: 0.9781 < μ < 1.0331. Prediction Interval: 0.9186 ≤ Xn+1 ≤ 1.0926. Tolerance Interval (0.8937 and 1.1175). Insufficient data to compute for the Tolerance Interval
c. Insufficient data to compute. Missing the
d. CI on the mean: 0.9781 < μ < 1.0331. Prediction Interval: 0.9186 ≤ Xn+1 ≤ 1.0926. Tolerance Interval (0.8937 and 1.1175)
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