Statement Let V be any vector space and let x, y, z be in V. Prove that if x + z = y +z, then x = y. Proof piem Suppose V is any vector space and x, y, z are any vectors in V. Suppose x + z = y + z. Show that x = y Since z is in V, there exists a vector -z in V such that z + (-z) = 0 Thus, x + z = y + z (x+z) + (-z) = (y+z) + (-z) x + (z + (−z)) = y + (z+ (−z)) because x + 0 = y +0 because and thus x = y Therefore, x + z = y + z implies x = y, and V has the cancellation property. Allowed answers because addition is commutative implies and thus by properties of the zero vector. V is a vector space, V is closed under addition, V is closed under scalar multiplication, addition is commutative in V, addition is associative in V, the zero vector in V is an additive identity, additive inverses exist in V, 1 is a multiplicative identity, scalar multiplication is associative, scalar multiplication distributes over vector addition, scalar multiplication distributes over scalar addition
Statement Let V be any vector space and let x, y, z be in V. Prove that if x + z = y +z, then x = y. Proof piem Suppose V is any vector space and x, y, z are any vectors in V. Suppose x + z = y + z. Show that x = y Since z is in V, there exists a vector -z in V such that z + (-z) = 0 Thus, x + z = y + z (x+z) + (-z) = (y+z) + (-z) x + (z + (−z)) = y + (z+ (−z)) because x + 0 = y +0 because and thus x = y Therefore, x + z = y + z implies x = y, and V has the cancellation property. Allowed answers because addition is commutative implies and thus by properties of the zero vector. V is a vector space, V is closed under addition, V is closed under scalar multiplication, addition is commutative in V, addition is associative in V, the zero vector in V is an additive identity, additive inverses exist in V, 1 is a multiplicative identity, scalar multiplication is associative, scalar multiplication distributes over vector addition, scalar multiplication distributes over scalar addition
Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
Related questions
Question

Transcribed Image Text:Statement
Let V be any vector space and let x, y, z be in V. Prove that if x + z = y + z, then x = y.
Proof
Text Problem
Suppose V is any vector space and x, y, z are any vectors in V. Suppose x + z = y + z. Show that x = y
Since z is in V, there exists a vector -z in V such that
z + (-z) = 0
Thus, x + z = y + z
(x+z) + (-z) = (y+z) + (-z)
x + (z + (−z)) = y + (z+ (-z)) because
x+0=y+0
and thus x = y
Therefore, x + z = y + z implies x = y, and V has the cancellation property.
Allowed answers
because addition is commutative
implies
because
and thus
by properties of the zero vector.
V is a vector space, V is closed under addition, V is closed under scalar multiplication, addition is
commutative in V, addition is associative in V, the zero vector in V is an additive identity, additive inverses
exist in V, 1 is a multiplicative identity, scalar multiplication is associative, scalar multiplication distributes
over vector addition, scalar multiplication distributes over scalar addition
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