State the linear programming problem in mathematical terms, identifying the objective function and the constraints. A car repair shop blends oil from two suppliers. Supplier I can supply at most 48 gal with 3.6% detergent. Supplier II can supply at most 66 gal with 3% detergent. How much can be ordered from each to get at most 100 gal of oil with maximum detergent? OA. Maximize 0.030x +0.036y Subject to: xs48 y≤ 66 x+ys 100 OC. Maximize 48x + 66y Subject to: x248 y266 0.036x +0.03y2 100 CIT OB. Maximize 0.036x + 0.03y Subject to: 0≤x≤48 0sys 66 x+ys 100 O D. Maximize 48x + 66y Subject to: xs48 y≤ 66 0.036x +0.03ys 100

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
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**Linear Programming Problem: Maximizing Detergent in Oil Blending**

In this problem, the goal is to maximize the amount of detergent in oil blending using supplies from two suppliers, all while adhering to specific constraints.

**Objective:**
To find out how much oil should be sourced from each supplier to maximize the detergent content.

**Given:**
- Supplier I can provide a maximum of 48 gallons, each containing 3.6% detergent.
- Supplier II can supply a maximum of 66 gallons, each with 3% detergent.
- The total oil ordered should not exceed 100 gallons.

**Options for Objective Function and Constraints:**

**A.**
- **Objective:** Maximize \(0.036x + 0.036y\)
- **Constraints:**
  - \(x \leq 48\)
  - \(y \leq 66\)
  - \(x + y = 100\)

**B.**
- **Objective:** Maximize \(0.036x + 0.03y\)
- **Constraints:**
  - \(0 \leq x \leq 48\)
  - \(0 \leq y \leq 66\)
  - \(x + y = 100\)

**C.**
- **Objective:** Maximize \(48x + 66y\)
- **Constraints:**
  - \(x \geq 48\)
  - \(y \geq 66\)
  - \(0.036x + 0.03y \geq 100\)

**D.**
- **Objective:** Maximize \(48x + 66y\)
- **Constraints:**
  - \(x \leq 48\)
  - \(y \leq 66\)
  - \(0.036x + 0.03y \leq 100\)

**Explanation of Diagram (if any):**

No graph or diagram is provided in the text. Each option represents a different potential setup for the objective function and constraints in the linear programming model. The goal is to choose the correct setup that accurately represents the scenario described: maximizing the detergent with constraints on supply and total gallons.
Transcribed Image Text:**Linear Programming Problem: Maximizing Detergent in Oil Blending** In this problem, the goal is to maximize the amount of detergent in oil blending using supplies from two suppliers, all while adhering to specific constraints. **Objective:** To find out how much oil should be sourced from each supplier to maximize the detergent content. **Given:** - Supplier I can provide a maximum of 48 gallons, each containing 3.6% detergent. - Supplier II can supply a maximum of 66 gallons, each with 3% detergent. - The total oil ordered should not exceed 100 gallons. **Options for Objective Function and Constraints:** **A.** - **Objective:** Maximize \(0.036x + 0.036y\) - **Constraints:** - \(x \leq 48\) - \(y \leq 66\) - \(x + y = 100\) **B.** - **Objective:** Maximize \(0.036x + 0.03y\) - **Constraints:** - \(0 \leq x \leq 48\) - \(0 \leq y \leq 66\) - \(x + y = 100\) **C.** - **Objective:** Maximize \(48x + 66y\) - **Constraints:** - \(x \geq 48\) - \(y \geq 66\) - \(0.036x + 0.03y \geq 100\) **D.** - **Objective:** Maximize \(48x + 66y\) - **Constraints:** - \(x \leq 48\) - \(y \leq 66\) - \(0.036x + 0.03y \leq 100\) **Explanation of Diagram (if any):** No graph or diagram is provided in the text. Each option represents a different potential setup for the objective function and constraints in the linear programming model. The goal is to choose the correct setup that accurately represents the scenario described: maximizing the detergent with constraints on supply and total gallons.
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