Levi-Strauss Co manufactures clothing. The quality control department measures weekly values of differentsuppliers for the percentage difference of waste between the layout on the computer and the actual wastewhen the clothing is made (called run-up). The data is in the table, and there are some negative valuesbecause sometimes the supplier is able to layout the pattern better than the computer. Do the data showthat there is a difference between some of the suppliers? Test at the 1% level.Run-ups for Different Plants Making Levi Strauss ClothingPlantDifferencePlant 1Plant 1Plant 1Plant 1Plant 1Plant 1Plant 1Plant 1Plant 1Plant 1Plant 1Plant 1Plant 1Plant 1Plant 1Plant 1Plant 1Plant 1Plant 1Plant 1Plant 1Plant 1Plant 2Plant 2Plant 2Plant 2Plant 2Plant 2Plant 2Plant 2Plant 2Plant 2Plant 2Plant 2Plant 2Plant 2Plant 2Plant 2Plant 2Plant 2Plant 2Plant 2Plant 2Plant 2Plant 3Plant 3Plant 3Plant 3Plant 3Plant 3Plant 3Plant 3Plant 3Plant 3Plant 3Plant 3Plant 3Plant 3Plant 3Plant 3Plant 3Plant 3Plant 3Plant 4Plant 4Plant 4Plant 4Plant 4Plant 4Plant 4Plant 4Plant 4Plant 4Plant 4Plant 4Plant 4Plant 4Plant 4Plant 4Plant 4Plant 4Plant 4Plant 5Plant 5Plant 5Plant 5Plant 5Plant 5Plant 5Plant 5Plant 5Plant 5Plant 5Plant 5Plant 5Plant 5Plant 3Plant 511.93.9-10.68-1.47.5-7.7-10.2-3-4.62.62.43.65-422.37.29.50.95.56.722.619.66.614.111-9.746.90.91515.77.9244.3-4.6-6.527.3-1619-3019.20.3-20.14.65.47.57.71-2.18.215.419.26.33.3-0.78.711.2110.91514.23.913.214.86.49.310.611.83.76.810.115.24.510.38.812.86.876.914.9-7.413.910.923.714.117.32.211.96.78.217.78.512.1State the hypotheses.Ho: All the means are equal.H₂: At least one mean is different from the others. ✓ ✓oCalculate the F test statistic. Round to two decimal places.F-1.16Calculate the p-value. Round to four decimal places.p-value - 0.3340State your decision.Since p-value > V✓ơ*0.01, fail to rejectInterpret the results.At the 1% significance level, there is notis✓✓✓ HoVevidence to show thatVa difference between some of the suppliers.

The quality control department measures weekly values of different suppliers for the percentage…

Answered: State the hypotheses. H₂: All the means…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Use technology to help you test the claim about the population mean, μ, at the given level of significance, α, using the given sample statistics. Assume the population is normally distributed. Claim: μ>1260; α=0.07; σ=198.95. Sample statistics: x=1275.29, n=275 Identify the null and alternative hypotheses. Choose the correct answer below. A. H0: μ≤1275.29 Ha: μ>1275.29 B. H0: μ≥1260 Ha: μ<1260 C. H0: μ>1275.29 Ha: μ≤1275.29 D. H0: μ≤1260 Ha: μ>1260 E. H0: μ≥1275.29 Ha: μ<1275.29 F. H0: μ>1260 Ha: μ≤
When we test Ho: μ = 0 against Ha: μ>0, we get a P-value of 0.03. a. What would the decision be for a significance level of 0.05? Interpret in context. b. If the decision in (a) is in error, what type of error is it? c. Suppose the significance level were instead 0.01. What decision would you make, and if it is in error, what type of error is it? a. What would the decision be for a significance level of 0.05? OA. We would decide not to reject the null hypothesis. We would have sufficient evidence that the population mean is different from 0. B. We would decide not to reject the null hypothesis. We would not have sufficient evidence that the population mean is different from 0. OC. We would decide to reject the null hypothesis. We would have sufficient evidence that the population mean is different from 0. O D. We would decide to reject the null hypothesis. We would not have sufficient evidence that the population mean is different from 0. b. If the decision in (a) is in error, what…
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Use technology to help you test the claim about the population mean, p, at the given level of significance, a, using the given sample statistics. Assume the population is normally distributed. Claim: u>1170; a=0.07; o = 204.05. Sample statistics: x = 1200.26, n 300 Identify the null and alternative hypotheses. Choose the correct answer below. O A. Ho: H> 1200.26 O B. H, p> 1170 Ha: ps 1200.26 Ha us1170 O C. Ho: H21170 D. Ho ps 1170 Ha: µ 1170 O E. Ho: us 1200.26 OF Ho p2 1200.26 Ha: p> 1200.26 H3 p< 1200.26 Calculate the standardized test statistic. The standardized test statistic is. (Round to two decimal places as needed.
mber This will jus. A data set includes data from student evaluations of courses. The summary statistics are n= 88, x=4.09, s 0.66. Use a 0.05 significance level to test the claim that the population of student course evaluations has a mean equal to 4.25. Assume that a simple random sample has been selected. Identify the null and alternative hypotheses, test statistic, P-value, and state the final conclusion that addresses the original claim. What are the null and alternative hypotheses? O A. Ho: H=4.25 Ημ 4.25 O B. H: p=4.25 Hp p*4.25 O C. Ho: u#4.25 H: =4.25 O D. Ho p=4.25 H: p>4.25 Determine the test statistic. - 1.85 (Round to two decimal places as needed.) Determine the P-value. (Round to three decimal places as needed.) State the final conclusion that addresses the original claim. V Ho. There is evidence to conclude that the mean of the population of student course evaluations is equal to 4.25 correct.
ch Assume that you plan to use a significance level of a = 0.05 to test the claim that p₁ = P2. Use the given sample sizes and numbers of successes to find the pooled estimate p. Round your answer to the nearest thousandth. n₁ =677, n₂ = 3377 x₁ = 172, x₂=654 OA. 0.408 OB. 0.452 OC. 0.204 OD. 0.163 Et Time Remaining: 01:35:15 Snowing now O dx Next 12:20 PM 12/11/2022 C E
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Use technology help you test the claim about the population mean, μ, at the given level of significance, , using the given sample statistics. Assume the population is normally distributed. Claim: μ> 1270; x = 0.02; a=214.81. Sample statistics: x= 1293.27, n = 275 Identify the null and alternative hypotheses. Choose the correct answer below. OA. Ho: H> 1270 Ha: μ≤ 1270 c. Ho: Hs 1270 H₂: > 1270 OE. Ho: s1293.27 H₂: > 1293.27 Calculate the standardized test statistic. The standardized test statistic is 1.80 (Round to two decimal places as needed.) Determine the P-value. P= (Round to three decimal places as needed.) OB. Ho: μ21270 Ha: 1293.27 H₂: s1293.27 OF. Ho: 21293.27 H₂: <1293.27
The average American gets a haircut every 43 days. Is the average different for college students? The data below shows the results of a survey of 11 college students asking them how many days elapse between haircuts. Assume that the distribution of the population is normal. 32, 46, 49, 45, 50, 49, 43, 45, 38, 46, 42 What can be concluded at the the a =0.01 level of significance level of significance? a. For this study, we should use Select an answer b. The null and alternative hypotheses would be: Họ: ? Select an answer v H. Select an answer Y C. The test statistic ? (please show your answer to 3 decimal places.) d. The p-value - (Please show your answer to 3 decimal places.) e. The p-value is 2 f. Based on this, we should Select an answer the null hypothesis, g. Thus, the final conclusion is that, The data suggest the populaton mean is significantly different from 43 ata = 0.01, so there is fficient evidence tr conrlide that -he nonulation.
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Answer+ 14. For each of the following three sample sizes, construct the 95% confidence interval for the population proportion. Use a sample proportion of 0.40 throughout. What happens to interval width as sample size increases? Why? P = 0.40 Sample A: N= 100 Sample B: N 1000 Sample C: N= 10,000 7.15. PS Two individuals are running for mayor of a large city. You conduct an election survey a week before the election and find that 51% of the respondents prefer candidate A. Can you predict a winner? Use the 99% level. (HINT: In a two-candidate race, what percentage of the vote would the winner need? Does the confidence interval indicate that candidate A has a sure margin of victory? 72°F 409 4. 141 44 Insert 96 4 G.

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