Starting from the internal energy equation, using the relations for enthalpy h = e + p/p and hT = h + u for the total enthalpy, get the following energy equation. Dhr Dt P- = p др д + div(kVT) + ox, -(Tij'ui) + pfiui
Starting from the internal energy equation, using the relations for enthalpy h = e + p/p and hT = h + u for the total enthalpy, get the following energy equation. Dhr Dt P- = p др д + div(kVT) + ox, -(Tij'ui) + pfiui
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![Starting from the internal energy equation, using the relations for enthalpy h = e + p/p and hT = h + u?/2
for the total enthalpy, get the following energy equation.
DhT
др
+ div(kVT) +
at
a (Tij'u;) + pfiu;
Dt](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Faa2234a1-a525-4d5a-8356-3d1b5620c498%2F78ab4e8f-8fad-4102-89d4-09aa67a59db1%2Fo0cxw5_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Starting from the internal energy equation, using the relations for enthalpy h = e + p/p and hT = h + u?/2
for the total enthalpy, get the following energy equation.
DhT
др
+ div(kVT) +
at
a (Tij'u;) + pfiu;
Dt
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