standard deviation of 90 pounds. The company believes that, due to an improvement in the manufacturing process, mean breaking strength, μ, of the cables is now greater than 1775 pounds. To see if this is the case, 39 newly manufactured cables are randomly chosen and tested, and their mean breaking strength is found to be 1810 pound Assume that the population is normally distributed. Can we support, at the 0.10 level of significance, the claim that population mean breaking strength of the newly-manufactured cables is greater than 1775 pounds? Assume that th population standard deviation has not changed. Perform a one-tailed test. Then complete the parts below. Carry your intermediate computations to three or more decimal places, and round your responses as specified below necessary, consult a list of formulas.) (a) State the null hypothesis Ho and the alternative hypothesis H₁. Ho :O H₁:0 (b) Determine the type of test statistic to use. (Choose one) (c) Find the value of the test statistic. (Round to three or more decimal places.) 0 H XI 0=0 D S Р OSO ê ㅁㅁㅁ 020 0#0 OO
standard deviation of 90 pounds. The company believes that, due to an improvement in the manufacturing process, mean breaking strength, μ, of the cables is now greater than 1775 pounds. To see if this is the case, 39 newly manufactured cables are randomly chosen and tested, and their mean breaking strength is found to be 1810 pound Assume that the population is normally distributed. Can we support, at the 0.10 level of significance, the claim that population mean breaking strength of the newly-manufactured cables is greater than 1775 pounds? Assume that th population standard deviation has not changed. Perform a one-tailed test. Then complete the parts below. Carry your intermediate computations to three or more decimal places, and round your responses as specified below necessary, consult a list of formulas.) (a) State the null hypothesis Ho and the alternative hypothesis H₁. Ho :O H₁:0 (b) Determine the type of test statistic to use. (Choose one) (c) Find the value of the test statistic. (Round to three or more decimal places.) 0 H XI 0=0 D S Р OSO ê ㅁㅁㅁ 020 0#0 OO
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
Related questions
Question
SEVENTEEN
Options for part (b)
a. "Z" b. "t" c. "Chi-square" d. "F"
Transcribed Image Text:The breaking strengths of cables produced by a certain manufacturer have historically had a mean of 1775 pounds and a
standard deviation of 90 pounds. The company believes that, due to an improvement in the manufacturing process, the
?
mean breaking strength, μ, of the cables is now greater than 1775 pounds. To see if this is the case, 39 newly
manufactured cables are randomly chosen and tested, and their mean breaking strength is found to be 1810 pounds.
Assume that the population is normally distributed. Can we support, at the 0.10 level of significance, the claim that the
population mean breaking strength of the newly-manufactured cables is greater than 1775 pounds? Assume that the
population standard deviation has not changed.
Perform a one-tailed test. Then complete the parts below.
Carry your intermediate computations to three or more decimal places, and round your responses as specified below. (If
necessary, consult a list of formulas.)
(a) State the null hypothesis Ho and the alternative hypothesis H₁.
Ho :
H₁ :0
(b) Determine the type of test statistic to use.
(Choose one)
(c) Find the value of the test statistic. (Round to three or more decimal places.)
(d) Find the p-value. (Round to three or more decimal places.)
(e) Can we support the claim that the population mean breaking strength of the
newly-manufactured cables is greater than 1775 pounds?
OYes O No
H
X
0=0
O
S
00
☐#0 O<O
Р
<Q
OSO 020
5
00
O<O
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((SEVENTEEN))
(d) Find the p-value. (Round to three to or more decimal places.)
(e) Can we support the claim that the population mean breaking strength of the
newly-manufactured cables is greater than 1775 pounds?
O Yes O No
Solution
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