21) ### Probability Calculation for Normally Distributed Data**Question:**Assume that the readings at freezing on a bundle of thermometers are normally distributed with a mean of 0°C and a standard deviation of 1.00°C. A single thermometer is randomly selected and tested. Find the probability of obtaining a reading less than -0.749°C.**Solution:**\[ P(Z < -0.749) = \]**Instructions:**1. Convert the thermometer reading to a Z-score using the formula for a standard normal distribution.2. Use the standard normal distribution table or a calculator to find the probability corresponding to the Z-score.**Interactive Element:**- [Submit Question Button]#### Explanation:- **Mean (µ):** 0°C- **Standard deviation (σ):** 1.00°C- **Desired reading (X):** less than -0.749°CUse the Z-score formula:\[ Z = \frac{X - \mu}{σ} \]\[ Z = \frac{-0.749 - 0}{1.00} \]\[ Z = -0.749 \]Now, look up the Z-score of -0.749 in the standard normal distribution table or use a calculator to find the probability \( P(Z < -0.749) \). Once you find the probability, input the value in the provided box and submit your answer.**Tools/Resources:**- Z-score table- Online normal distribution calculator**Conclusion:**This statistical problem involves understanding and using concepts of normal distribution, mean, and standard deviation to find the probability for a given reading.

Name: 21) ### Probability Calculation for Normally Distributed Data**Questio
Uploaded: 2024-03-20T06:46:14.000Z
Channel: Bartleby
Description: 21) ### Probability Calculation for Normally Distributed Data**Question:**Assume that the readings at freezing on a bundle of thermometers are normally distributed with a mean of 0°C and a standard deviation of 1.00°C. A single thermometer is randoml

Math

Statistics

ssume that the readings at freezing on a bundle of thermometers are normally distributed wit ean of 0"C and a standard deviation of 1.00°C. A single thermometer is randomly selected and ested. Find the probability of obtaining a reading less than -0.749 C. (Z<- 0.749) = Submit Question