ssohs/3026619/variants/3026619/take/12/ = Governor's Next Generation Commis... >O O< Step 1 2 3 4 5 6 7 Explanation Assign the oxidation number. Split equation into two half- reactions. Identify the oxidized and reduced species. Balance atoms that are not hydrogen or oxygen. Compute electrons lost and gained. Complete the reaction. Check your work. DISMISS Show My Work On the left-hand side, Al is 0, S is +6, and O is -2. On the right-hand side, Al is +3, S is +6, O is -2, and H is +1. Al(s) →Al2(SO4)3(aq) and H₂SO4(aq)→ H2(g) Al was oxidized. H₂SO4 was reduced. You need 2 Al(s) on the left-hand side, and you need 3H₂SO4(aq) also on the left-hand side. 3 electrons lost in oxidation 1 electron gained in reduction You need 3H2(g). This gives 2Al(s) + 3H₂SO4(aq) → Al2(SO4)3(aq) + H2(g)- The aluminum reaction lost 3 electrons and there is one instance of that. The sulfuric acid (H₂SO4) reaction gained 1 electron and there are 3 instances of that. It is balanced. All Changes Saved Continue

Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Indicate which dots are mistakes ty

Alert 1 of 1: Governor's Next Generation Commis...
HOTSPOT ANSWER
A learner submits the table below to show how the following unbalanced re-
action should be balanced.
Al(s) + H₂SO4 (aq) → Al₂(SO4)3(aq) + H 2(g)
However, the learners has made some mistakes. Press the hotspots of all the
cells in the table below that contain mistakes.
Step
1
2
3
Explanation
Assign the
oxidation
number.
4
Split equation
into two half-
reactions.
Identify the
oxidized and
reduced species.
Balance atoms
that are not
á ð ó ó ó ó ó óoðonoð
DISMISS
J
Show My Work
On the left-hand side, Al is 0, S is +6, and O is
-2. On the right-hand side, Al is +3, S is +6, O
is -2, and H is +1.
Al(s)
Al2(SO4)3(aq) and H₂SO4(aq)→ H2(g)
Al was oxidized.
H₂SO4 was reduced.
You need 2 Al(s) on the left-hand side, and you
need 3H₂SO
also on the left-hand side.
K
Continue
De
Transcribed Image Text:Alert 1 of 1: Governor's Next Generation Commis... HOTSPOT ANSWER A learner submits the table below to show how the following unbalanced re- action should be balanced. Al(s) + H₂SO4 (aq) → Al₂(SO4)3(aq) + H 2(g) However, the learners has made some mistakes. Press the hotspots of all the cells in the table below that contain mistakes. Step 1 2 3 Explanation Assign the oxidation number. 4 Split equation into two half- reactions. Identify the oxidized and reduced species. Balance atoms that are not á ð ó ó ó ó ó óoðonoð DISMISS J Show My Work On the left-hand side, Al is 0, S is +6, and O is -2. On the right-hand side, Al is +3, S is +6, O is -2, and H is +1. Al(s) Al2(SO4)3(aq) and H₂SO4(aq)→ H2(g) Al was oxidized. H₂SO4 was reduced. You need 2 Al(s) on the left-hand side, and you need 3H₂SO also on the left-hand side. K Continue De
Alert 1 of 1: Governor's Next Generation Commis...
HOTSPOT ANSWER
A learner submits the table below to show how the following unbalanced re-
action should be balanced.
Al(s) + H₂SO4 (aq) → Al₂(SO4)3(aq) + H 2(g)
However, the learners has made some mistakes. Press the hotspots of all the
cells in the table below that contain mistakes.
Step
1
2
3
Explanation
Assign the
oxidation
number.
4
Split equation
into two half-
reactions.
Identify the
oxidized and
reduced species.
Balance atoms
that are not
á ð ó ó ó ó ó óoðonoð
DISMISS
J
Show My Work
On the left-hand side, Al is 0, S is +6, and O is
-2. On the right-hand side, Al is +3, S is +6, O
is -2, and H is +1.
Al(s)
Al2(SO4)3(aq) and H₂SO4(aq)→ H2(g)
Al was oxidized.
H₂SO4 was reduced.
You need 2 Al(s) on the left-hand side, and you
need 3H₂SO
also on the left-hand side.
K
Continue
De
Transcribed Image Text:Alert 1 of 1: Governor's Next Generation Commis... HOTSPOT ANSWER A learner submits the table below to show how the following unbalanced re- action should be balanced. Al(s) + H₂SO4 (aq) → Al₂(SO4)3(aq) + H 2(g) However, the learners has made some mistakes. Press the hotspots of all the cells in the table below that contain mistakes. Step 1 2 3 Explanation Assign the oxidation number. 4 Split equation into two half- reactions. Identify the oxidized and reduced species. Balance atoms that are not á ð ó ó ó ó ó óoðonoð DISMISS J Show My Work On the left-hand side, Al is 0, S is +6, and O is -2. On the right-hand side, Al is +3, S is +6, O is -2, and H is +1. Al(s) Al2(SO4)3(aq) and H₂SO4(aq)→ H2(g) Al was oxidized. H₂SO4 was reduced. You need 2 Al(s) on the left-hand side, and you need 3H₂SO also on the left-hand side. K Continue De
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