ssf60 ssf60 ssfo ´0 ssf60 ssf60 ssf60 ssf60 ssf6° 5. A large box is pulled by a person with a force F as shown in the figure. The angle 8 = 25°. What is the magnitude of the normal force at the moment when the box is about to move if the mass of the box is m = 23.5 kg and the coeff of static friction between the box and the floor is 0.64? 8 TG ssf60 ssf60 ssf60 ssfó ƒ60 ssf60 ssf60 ssf60 s ssf60f50 s$£60sf60 ssf60 ssf6 50 s 6sfossf60 ssf50 ssf60 st 09Jss

Physics for Scientists and Engineers: Foundations and Connections
1st Edition
ISBN:9781133939146
Author:Katz, Debora M.
Publisher:Katz, Debora M.
Chapter6: Applications Of Newton’s Laws Of Motion
Section: Chapter Questions
Problem 43PQ: Your sailboat has capsized! Fortunately, you are no longer aboard the boat. Instead, you are hanging...
icon
Related questions
Question
### Problem 5: Determining the Normal Force on a Box

A large box is pulled by a person with a force \( \vec{F} \) as illustrated in the figure below. The angle \( \theta \) between the force vector and the horizontal surface is \( 25^\circ \). Given that the mass of the box is \( m = 23.5 \) kg and the coefficient of static friction between the box and the floor is \( 0.64 \), calculate the magnitude of the normal force exerted on the box at the moment when it is just about to move.

#### Details and Diagram

- **Mass of the box (m)**: 23.5 kg
- **Coefficient of static friction (\( \mu_s \))**: 0.64
- **Angle (\( \theta \))**: \( 25^\circ \)

![Diagram Showing Force \( \vec{F} \) Applied at an Angle \( \theta \)](image_link)

In the diagram, the force \( \vec{F} \) is applied at an angle \( \theta \) of \( 25^\circ \) above the horizontal. The forces acting on the box need to be analyzed to determine the normal force acting on it just as it is about to move.

To find the normal force,
\[ N = mg - F \sin(\theta) \]

Where:
- \( N \) is the normal force.
- \( m \) is the mass of the box.
- \( g \) is the acceleration due to gravity (approximately \( 9.81 \, \text{m/s}^2 \)).
- \( F \) is the applied force.
- \( \theta \) is the angle of the applied force from the horizontal.

Given this setup, the applied force \( \vec{F} \) can be further analyzed including its horizontal and vertical components. The normal force can be precisely determined by resolving all the vertical components acting on the box including the effect of \( \vec{F} \). 

This equation explains the reduction in normal force due to the vertical component of the applied force \( F \).

This problem is an excellent example of static equilibrium and the application of Newton's laws in two dimensions. Students should consider breaking down the forces into their components and applying the equilibrium conditions to solve for the normal force.
Transcribed Image Text:### Problem 5: Determining the Normal Force on a Box A large box is pulled by a person with a force \( \vec{F} \) as illustrated in the figure below. The angle \( \theta \) between the force vector and the horizontal surface is \( 25^\circ \). Given that the mass of the box is \( m = 23.5 \) kg and the coefficient of static friction between the box and the floor is \( 0.64 \), calculate the magnitude of the normal force exerted on the box at the moment when it is just about to move. #### Details and Diagram - **Mass of the box (m)**: 23.5 kg - **Coefficient of static friction (\( \mu_s \))**: 0.64 - **Angle (\( \theta \))**: \( 25^\circ \) ![Diagram Showing Force \( \vec{F} \) Applied at an Angle \( \theta \)](image_link) In the diagram, the force \( \vec{F} \) is applied at an angle \( \theta \) of \( 25^\circ \) above the horizontal. The forces acting on the box need to be analyzed to determine the normal force acting on it just as it is about to move. To find the normal force, \[ N = mg - F \sin(\theta) \] Where: - \( N \) is the normal force. - \( m \) is the mass of the box. - \( g \) is the acceleration due to gravity (approximately \( 9.81 \, \text{m/s}^2 \)). - \( F \) is the applied force. - \( \theta \) is the angle of the applied force from the horizontal. Given this setup, the applied force \( \vec{F} \) can be further analyzed including its horizontal and vertical components. The normal force can be precisely determined by resolving all the vertical components acting on the box including the effect of \( \vec{F} \). This equation explains the reduction in normal force due to the vertical component of the applied force \( F \). This problem is an excellent example of static equilibrium and the application of Newton's laws in two dimensions. Students should consider breaking down the forces into their components and applying the equilibrium conditions to solve for the normal force.
Expert Solution
steps

Step by step

Solved in 2 steps with 1 images

Blurred answer
Knowledge Booster
Third law of motion
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.
Similar questions
  • SEE MORE QUESTIONS
Recommended textbooks for you
Physics for Scientists and Engineers: Foundations…
Physics for Scientists and Engineers: Foundations…
Physics
ISBN:
9781133939146
Author:
Katz, Debora M.
Publisher:
Cengage Learning
Physics for Scientists and Engineers, Technology …
Physics for Scientists and Engineers, Technology …
Physics
ISBN:
9781305116399
Author:
Raymond A. Serway, John W. Jewett
Publisher:
Cengage Learning
Principles of Physics: A Calculus-Based Text
Principles of Physics: A Calculus-Based Text
Physics
ISBN:
9781133104261
Author:
Raymond A. Serway, John W. Jewett
Publisher:
Cengage Learning
Physics for Scientists and Engineers with Modern …
Physics for Scientists and Engineers with Modern …
Physics
ISBN:
9781337553292
Author:
Raymond A. Serway, John W. Jewett
Publisher:
Cengage Learning
Physics for Scientists and Engineers
Physics for Scientists and Engineers
Physics
ISBN:
9781337553278
Author:
Raymond A. Serway, John W. Jewett
Publisher:
Cengage Learning
College Physics
College Physics
Physics
ISBN:
9781938168000
Author:
Paul Peter Urone, Roger Hinrichs
Publisher:
OpenStax College