SSED THIS? Watch KCV: Limiting Reactant, Theoretical Yield, and Percent Yield, IWE: Limiting Reactant and Theoretical Yield; Read Section 4.4. You can click on the Review link to access the section in your eText. Iron(II) sulfide reacts with hydrochloric acid according to the reaction FeS (s) + 2HCl(aq) →FeCl₂ (aq) + H₂S (s) A reaction mixture initially contains 0.212 mol FeS and 0.636 mol HCl. Once the reaction has reached completion, what amount (in moles) of the excess reactant is left? Express the answer in moles to three significant figures. n = Templates Symbols undo rego reset keyboard shortcuts help 2/ Submit Request Answer mol

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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
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MISSED THIS? Watch KCV: Limiting Reactant, Theoretical Yield,
and Percent Yield, IWE: Limiting Reactant and Theoretical
Yield; Read Section 4.4. You can click on the Review link to
access the section in your eText.
Iron(II) sulfide reacts with hydrochloric acid according to the
reaction
FeS(s) + 2HCl(aq)→FeCl2 (aq) + H₂S(s)
A reaction mixture initially contains 0.212 mol FeS and 0.636
mol HCl.
Part A
Once the reaction has reached completion, what amount (in moles) of the excess reactant is left?
Express the answer in moles to three significant figures.
n =
Templates Symbols undo redo reset keyboard shortcuts help
2/
Submit
Request Answer
>
mol
Transcribed Image Text:MISSED THIS? Watch KCV: Limiting Reactant, Theoretical Yield, and Percent Yield, IWE: Limiting Reactant and Theoretical Yield; Read Section 4.4. You can click on the Review link to access the section in your eText. Iron(II) sulfide reacts with hydrochloric acid according to the reaction FeS(s) + 2HCl(aq)→FeCl2 (aq) + H₂S(s) A reaction mixture initially contains 0.212 mol FeS and 0.636 mol HCl. Part A Once the reaction has reached completion, what amount (in moles) of the excess reactant is left? Express the answer in moles to three significant figures. n = Templates Symbols undo redo reset keyboard shortcuts help 2/ Submit Request Answer > mol
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